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baudrunner · 02-23-2006, 08:31 PM

Oh, I see. So where ± = neutral, or equilibrium therefore ...

Sk p(yin,yang) q(yang,yin) - q(yin,yang) p(yang,yin) = ± ...(?!?!?!)

but hang on, something's not right..

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baudrunner 4th degree Black Belt Status: Offline Posts: 586 Thanks Given: 1 Thanked 37x in 34 Posts Join Date: Dec 2005 Rep Power: 17	02-23-2006, 08:31 PM Oh, I see. So where ± = neutral, or equilibrium therefore ... Sk p(yin,yang) q(yang,yin) - q(yin,yang) p(yang,yin) = ± ...(?!?!?!) but hang on, something's not right.. "There is nothing permanent except change"