| Re: The Causal Identity of Gravity
Quote:
Originally Posted by MJA  Just One question if you please,
In the above equation: What is the numerical equivalence of F?
Thanks,
MJA | MJA ... It would be in Kilograms/metre2 (metre squared). You only need to know what the two objects "weigh" in kilograms and the distance between them. If you are usings pounds and yards then the value of the gravitational constant would also have a different value. Otherwise it would not be a constant, which means it has a fixed value regardless of the 'numerical rulers' being used. This is one of the reasons why matter is 'atomic' or 'discontinuous' in structure. IMO
hope this helped ... greg
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