Theory of Everything - View Single Post - The 'Event Horizon' (A can of wormholes?)

everymansmedium · **Re: The 'Event Horizon' (A can of wormholes?) -** 11-28-2007, 12:40 PM

Dispersal of energy is always in a sphere. The energy disperses according to the square law. The square law was originally discovered as a result of comparison to the surface area of a sphere. The surface area increases as to the square of the radius.

If you have x number of square (inches/feet/miles) if r is times 2 then the area is 2^2 = 4
If the energy is dispersed over 4 times the area then the energy available in any specified area will be ¼
Or 1/r^2=E.

The bending of the light. Hold up something that will block the light. Put a hole in it. Now the light shines through the hole. Now you have a beam of light coming through the hole. I am sure that you can imagine bending this beam. Now if you take the item that was blocking some of the light away. The light that was shining through the hole will still be there and will still be bent but it will not be so obvious. The result will be evident by a non linear dispersal of the light. It will be brighter in some areas than it is in others. It is this variation in the intensity in one place relative to another from a specific source that will be indicative of the light from that distant source being effected by some potential interfering source.

John.

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everymansmedium 2nd degree Black Belt Status: Offline Posts: 301 Thanks Given: 56 Thanked 48x in 37 Posts Join Date: Sep 2007 Rep Power: 7	Re: The 'Event Horizon' (A can of wormholes?) - 11-28-2007, 12:40 PM Dispersal of energy is always in a sphere. The energy disperses according to the square law. The square law was originally discovered as a result of comparison to the surface area of a sphere. The surface area increases as to the square of the radius. If you have x number of square (inches/feet/miles) if r is times 2 then the area is 2^2 = 4 If the energy is dispersed over 4 times the area then the energy available in any specified area will be ¼ Or 1/r^2=E. The bending of the light. Hold up something that will block the light. Put a hole in it. Now the light shines through the hole. Now you have a beam of light coming through the hole. I am sure that you can imagine bending this beam. Now if you take the item that was blocking some of the light away. The light that was shining through the hole will still be there and will still be bent but it will not be so obvious. The result will be evident by a non linear dispersal of the light. It will be brighter in some areas than it is in others. It is this variation in the intensity in one place relative to another from a specific source that will be indicative of the light from that distant source being effected by some potential interfering source. John. Creator of Silence.