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The "r" is not a constant. As a position vector its scalar product with absolute acceleration is a constant square of light speed.
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*** I don't follow this. Do you care to explain? Are you saying that r x g = c^2?
The acceleration due to gravity has nothing to do with the speed of light in my view but if you think it does you are free to produce your argument or evidence to support this your point of view.
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So if r approaches infinity then the absolute acceleration approaches zero.
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*** And infinity x 0 is?
Recall you said when g = 0, M = 0 implying that infinity x 0 = 0 which is incorrect in my view.
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From Galileo's experiments it was proven that the local acceleration of gravity small g does not depend on the inertial mass m. It depends on the big mass M. more later.
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*** Agreed, I also hold that M determines g.
Roger