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neutralino · **Re: Quest into arena of Classical mechanics -** 01-30-2008, 07:07 PM

F=ma is perfectly valid as it stands. It doesn't make much sense to be talking about changes in force, since the reference value will always be zero. That is, zero force gives no acceleration, and thus if one assigns a non-zero force to a body, the acceleration will be non zero.

Of course, the more general form of the equation is $F=\frac{dp}{dt}$ ; i.e. the force is equal to the time rate of change of momentum. For normal bodies with constant mass, this reduces to the well known expression of Newton's second law.

Since this thread is discussing physics, it is more suited to the physics forums than the introductions forum and thus I am moving it there. Welcome to the forums, BTW, Arpan.

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neutralino Master Status: Offline Posts: 729 Thanks Given: 30 Thanked 111x in 94 Posts Join Date: Oct 2007 Rep Power: 12 Awards Showcase Total Awards: 1	Re: Quest into arena of Classical mechanics - 01-30-2008, 07:07 PM F=ma is perfectly valid as it stands. It doesn't make much sense to be talking about changes in force, since the reference value will always be zero. That is, zero force gives no acceleration, and thus if one assigns a non-zero force to a body, the acceleration will be non zero. Of course, the more general form of the equation is $F=\frac{dp}{dt}$ ; i.e. the force is equal to the time rate of change of momentum. For normal bodies with constant mass, this reduces to the well known expression of Newton's second law. Since this thread is discussing physics, it is more suited to the physics forums than the introductions forum and thus I am moving it there. Welcome to the forums, BTW, Arpan. ~neutralino If you haven't found something strange during the day, it hasn't been much of a day - John A. Wheeler.