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Re: rational polygons
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AntonioLao
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Re: rational polygons -
01-31-2008, 02:49 PM
Quote:
Originally Posted by
mkirkpatrick
mostly invisible
In mathematics, if a transformation does not exist between two domains then they are conversely invisible to each other.
Time independence:
[∂
E(
g)
]²=[∂
F
(
a
)
×∂
r
(
a
)
]
·
[∂
F
(
b
)
×∂
r
(
b
)
] and Mass independence:
¶
a
(
t
)·
¶
r
(
t
)=
c
²
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