| Re: Quest into arena of Classical mechanics -
02-02-2008, 09:18 AM
Quote:
Originally Posted by ARPAN  let F(x)= x^2
then we get its derivative as 2x
the same function can be represented as F(x)=x.x.x.x......... x times | The problem is in your definition here. F(x)=x^2=x.x. Differentiating this, by the product rule, gives dF/dx=1.x+1.x=2x, as above.
The second function you describe is F(x)=x^x.
~neutralino If you haven't found something strange during the day, it hasn't been much of a day - John A. Wheeler. |