Thread: to e or not to e
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Re: to e or not to e
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AntonioLao
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Re: to e or not to e - 02-07-2008, 12:34 PM
Quote:
Originally Posted by mkirkpatrick
I hope that if the ship comes ashore there is no boson
on board
That is absolutely true. You see, if we take the square of a singular Hadamard matrix that is to say multiply by itself and the fact that it is a differential domain then the product is zero.

Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(t)·r(t)=c²
  
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