Thread: sleepless eyes
View Single Post
AntonioLao
Raider of the lost time

AntonioLao's Avatar

Join Date: Nov 2003
Posts: 6,329
Blog Entries: 6
89 AntonioLao is a splendid one to beholdAntonioLao is a splendid one to beholdAntonioLao is a splendid one to beholdAntonioLao is a splendid one to behold
Quote  
03-20-2008, 02:42 PM
sleepless eyes

The sleepless eyes of the GPS satellites continuously watch over the earth until their inevitable orbital decays, on board backup electrical batteries, and solar panels gave up their fight against the forces of gravity and inertia. In reality, they are not eyes at all but beacons of electromagnetic radiations transmitted at constant frequency. Receiving these signals from these outer space lighthouses could help locating all earthbound positions of space and time for all air, land, and sea navigation.

The truly sleepless eyes are the weather and spy satellites. The first kind watch over earth’s dynamic but chaotic climatic changes to reach predictability of upcoming atmospheric activities. On the other hand, the spy satellites watch over countries in order to determine ongoing local national activities that will eventually affect the peace equation between global powers. Both rely on the science of on board remote sensors. These could differentiate the thermal footprints with differences of few kelvins or even fractions of a Kelvin. However, if the ambient temperature underload or overload the lower or upper limit of sensor’s thresholds then all of them see nothing, analogous to staring at the absolute darkness of deep space between stars during moonless nights. Therefore, an all powerful sleepless eye could not have detected the random quantum vacuum fluctuations of space-time unless its wavelength threshold is shorter than Planck length but at this domain of space-time all physical laws breakdown and rendered meaningless. Nevertheless, the sleepless all Seeing Eye must be the singular absolute consciousness itself in order for anything to exist as positive and negative polarization of light.
__________________
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
Reply With Quote
AntonioLao is offline
 
Posicionamiento en buscadores | Loans | Debt Consolidation | Myspace Codes | Best Credit Cards