| Re: photon accelerator? -
04-11-2008, 01:50 PM
If I can accelerate today's light to see tomorrow's light then catch the return reflections in the magic mirror then I know which numbers to play for all future lottery drawings.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
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