| Re: spacetime ohm
Thanks. If these are represented by Hadamard matrices then their products give squares of energy. I'm starting to use them to represent the conductivity tensor of superconductivity.
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Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
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