| Re: Who gonna prove Goldbach conjecture?
There is now a simple algorithmic proof of this conjecture. Maybe a conference is needed to finally announce it to the public.
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Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
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