Thanks davidgow77 for asking a question I've often wondered about.
From Wikipedia, the
radius of the observable universe is about 46 billion light years.
So, the volume of the observable universe is
\frac{4}{3} \times \pi \times \mathrm{R}^3 = 4 \times 10^{32}\text{ ly}^3
with R = 46 billion light years according to Wikipedia and my own calculations.
The same Wikipedia article estimates the visible mass in that volume as
9 \times 10^{21} \ \textrm{solar masses}
or about
1.8 \times 10^{52}\ \textrm{kg} if one solar mass = 2 \times 10^{30}\ \textrm{kg}
Since visible matter is less than 5% of the total matter in the universe, I guess the total is
3.6 \times 10^{53}\ \textrm{kg}
or more.
Wikipedia gave me the
dark matter estimate as 22% and the dark energy as 74%
No doubt you have much better answers by now, but this has been a good exercise for me. I suspect I have a bit to learn regarding this editor and how it handles tags.
Thanks