“Gooooooooooaaaaaaaaaallllllllll…! Pi is mine now!”
“The caravan of digits that is pi
does not stop at the edge of the page,
but runs off the table and into the air,
over the wall, a leaf, a bird's nest, the clouds, straight into the sky,
through all the bloatedness and bottomlessness.
Oh how short, all but mouse-like is the comet's tail!”
(Wislawa Szymborska)
I will prove that “pi” equals 3 plus the Square Root of 2!
Let’s write both constants first:
Pi:
3. 14159 26535 8979323
Square Root of 2:
1. 41421 3562373
I will make the necessary conversions (not many though!) on “pi” first:
14159 26535 8979323
141 [59] 2 [65] 358 [979] 323!
141 [4] 2 [1] 358 [4 + 2 + 4] 323!
141421358[10 = 0] 323!
*10 and 0 are the beginning of a cycle. See the Mayan numbers. Observe that converting 9 into 4 and 6 into 1 we had to ‘reduced’ in two-half cycles (one complete cycle) or [-10] that compensated the imbalance created by [10] as the result of [4 + 2 + 4]!
I used five conversions which is an ODD one meaning that still there is a “half-cycle” accounted for…
141 421 358 323! This is the final number! Plus “half-cycle”!
This is the Square Root of 2:
141421 3562373
14142 135 [6 + 2] 3[7]3!
141 421 35[6 + 2] 3 [2] 3!
141 421 358 323!
*Since I only converted 7 into 2, I have produced an ODD conversion “owing ‘half-cycle’ to the final results” and that was the same solution in “pi” as well!
141 421 358 323! And 141 421 358 323!
Exactly the same number!!!
"I, Miguel De Zayas hereby officially claim that I found the “hidden connection” between “pi” and “Square Root of 2” the 9th of August of 2010."
YOU TOO ARE INVITED TO THE PARTY… WOULD YOU LIKE TO HAVE A PIECE OF MY PIE?
http://en.wikipedia.org/wiki/File:Pi_pie2.jpg
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