[N0B0DY]

What if the proton consisted of approx. 917 electrons and 918 positrons?

[neutralino]

Originally Posted by N0B0DY

What if the proton consisted of approx. 917 electrons and 918 positrons?

It couldn't because the electrons and positrons would annihilate! Besides, even if you scenario could happen, the proton would still have net positive charge, and my argument applies as in the previous post.

It seems like you're trying to test me here, nobody.

[PoPpAScience]

Originally Posted by neutralino

The gravitational force acts on all scales, that is, its range is infinite, whereas the nuclear forces only act on scales less than the diameter of the nucleus of an atom. Therefore I don't see how one can propose linking the two on mascroscopic levels.

OK. I understand about the basic forces within the nucleus. What about the "residual strong force", even though it is smaller than the forces working within the particles? With the huge amount of nucleons in a planet. Is there a chance that the a polarization effect could act like gravity? Could the combined total of all the "residual strong force" in a Planet have an effect like Gravity?

[N0B0DY]

It is a test, neutralino, to see if you are willing to think outside the box so to speak. You are apparently very intelligent, but to conform to consensus won't make you like Einstein which is what I am looking for, another Einstein.

The particles would annihilate, continually, the electrons would fall into the nuclei repeatedly, yes, but the annihilation would produce photons which collide with absorbed photons to create new particle pairs, as per the repeatable experiments performed at SLAC, and as per their hypothesized kinetic energy model, the high-energy gamma bursts would explain the masses of the unnecessary W-Z bosons.

Only the left-handed, forward-time, electrons are observed because observations are limited to forward-time, so the positrons being right-handed, backward-time, are undetectable in nature.

[N0B0DY]

"Is there a chance that the a polarization effect could act like gravity?"

Would this have anything to do with gravitomagnetism, Pop?

[PoPpAScience]

Originally Posted by N0B0DY

"Is there a chance that the a polarization effect could act like gravity?"

Would this have anything to do with gravitomagnetism, Pop?

To be honest I never heard of GEM before. I do not know how I missed it. Thanks Nobody. It looks at first glance, as exactly what I was trying to get at. I have to read more on it today.

[neutralino]

Originally Posted by N0B0DY

It is a test, neutralino, to see if you are willing to think outside the box so to speak. You are apparently very intelligent, but to conform to consensus won't make you like Einstein which is what I am looking for, another Einstein.

I don't want to be the next Einstein: I'm just starting out in my career and would like a job! Besides, upto now, you've not given me anything to think outside of the box with!

The particles would annihilate, continually, the electrons would fall into the nuclei repeatedly, yes, but the annihilation would produce photons which collide with absorbed photons to create new particle pairs, as per the repeatable experiments performed at SLAC, and as per their hypothesized kinetic energy model, the high-energy gamma bursts would explain the masses of the unnecessary W-Z bosons.

I can't comment on this, as I'm not a particle physicist. However, this scenario seems to me to be rather unstable whereas we know that protons are stable particles. Still, my point with respect to the overall charge of the nucleus still holds

[Profpat]

Hi Neutralino;

I know they consider the proton to be a stable particle because it doesn't decay into anything smaller ( quarks for instance ) but the proton can become a neutron and vice versa, and so to me they really are essentially the same particle. One with the electron inside ( the neutron ) One with the electron outside ( the proton ). Now here is the question the weight difference twixt these two particles is ~ 3' and the weight of the electron is assigned a weight of 1.
Is the difference of 2 manisfested by the energy holding the electron outside of itself?

It's the accountant in me that would like to account for this difference. Any help you can throw my way would be appreciated.

Best to all,

Pat

[neutralino]

Originally Posted by Profpat

Hi Neutralino;

[size=2]I know they consider the proton to be a stable particle because it doesn't decay into anything smaller ( quarks for instance ) but the proton can become a neutron and vice versa, and so to me they really are essentially the same particle.

Note that, while a neutron can decay to a proton, this doesn't happen the other way around.

One with the electron inside ( the neutron ) One with the electron outside ( the proton ).

The electron is not actually inside the neutron; this would not be allowed by the standard model, since only quarks are allowed inside the particles.

Neutrons decay under the weak force to produce a proton, an electron and an electron antineutrino (the neutrino must be there to conserve lepton number). Inside the particle, a down quark gets converted into an up quark, and this is where the energy to create the other particles comes from.

To be honest, Pat, I don't know much about this, since it gets very technical when talking about quarks etc. Here's a nice webpage which discusses the decay of the neutron: http://hyperphysics.phy-astr.gsu.edu...es/proton.html

I like the hyperphysics site; it's very useful! Anyway, I hope to be more helpful in any other questions you may have in future!

[Profpat]

Thanks Neutralino;

I'll leave you alone on this one since you're cosmologist and not a nuclear physicist but here is one instance where a proton decays into a neutron.

Proton-Proton Chain

(NOTE: It is important to remember that not all collisions result in a reaction taking place. If the energies and/or orientation of the particles aren't correct/sufficient, the particles will simply behave like marbles bouncing off each other. The percentage of successful collisions is actually very small.)
This process dominates in stars where the core temperature is less than 15,000,000 K (such as our sun). It consists of three reactions that result in the conversion of six protons into a He nucleus plus two residual protons. An important reaction in this process is that of "proton conversion." In this reaction, a proton is converted into a neutron. The positive charge and some excess energy is released through the emission of a positron (a positive electron) and a neutrino.



The first step in this process is the collision of two protons where proximity permits the strong nuclear force to bind them together. The resulting combination is not stable, and one of the protons will decay to become a neutron, and this forms a stable nucleus of deuterium. This step needs to occur twice.

Best to you,

Pat

P.S. Thanks for the URL