cosmological constant

AntonioLao · 12:21 PM

the absolute value of the cosmological constant is

$| \Lambda | < 3 \times 10^{-52}$ $m^{-2}$

reference: Ignacio Ciufolini and John Archibald Wheeler, 'Gravitation and Inertia,' Princeton, New Jersey, 1995.

Noting that the units is the inverse of area indicates that this constant can be used to transform continuous space into absolute acceleration.

Incremental continuous space is given by $S_i=cE_i$ , where c is the speed of light. For variable speeds $S_i=vE_i$ and this is transformable into the scalar product of inertial force and a rate of change of area.

$S_i=\mathbf{F_i} \cdot \frac{dA}{dt}$

the absolute acceleration is then given by

$a_i = \int \frac{1}{m_i} cE_i \Lambda dt$

$m_i$ is the incremental mass which can never be identically zero.

Guille · 06-10-2005, 01:02 PM

What does the cosmological constant represent?

What is it's numerical value? (if you can, in scietific notation)

What is it used for?

AntonioLao · 06-10-2005, 04:12 PM

GUILLE,

when Einstein introduced the cosmological constant into his field equations and afterward Hubble showed him the universal redshifts, Einstein called it the greatest blunder of his life.

The units is inverse of area and it is needed to validate the steady state theory of the universe. At that time, nobody believes the universe can expand or contract. So it is used to formulate a static universe.

http://scienceworld.wolfram.com/phys...lConstant.html

Guille · 03:16 AM

Isn't then the constant useless if it was made for a static universe, when ours clearly isn't one?

AntonioLao · 06-12-2005, 04:04 PM

Quote:

Originally Posted by GUILLE

Isn't then the constant useless if it was made for a static universe, when ours clearlly isn't one?

Recently, the cosmological constant has been revived in the context of inflationary theories and in connection with the problem of galaxy formation.

Coldcreation · 03:17 AM

Quote:

Originally Posted by AntonioLao

the absolute value of the cosmological constant is

$| \\Lambda | < 3 \\times 10^{-52}$ $m^{-2}$

reference: Ignacio Ciufolini and John Archibald Wheeler, 'Gravitation and Inertia,' Princeton, New Jersey, 1995.

Noting that the units is the inverse of area indicates that this constant can be used to transform continuous space into absolute acceleration.

Incremental continuous space is given by $S_i=cE_i$ , where c is the speed of light. For variable speeds $S_i=vE_i$ and this is transformable into the scalar product of inertial force and a rate of change of area.

$S_i=\\mathbf{F_i} \\cdot \\frac{dA}{dt}$

the absolute acceleration is then given by

$a_i = \\int \\frac{1}{m_i} cE_i \\Lambda dt$

$m_i$ is the incremental mass which can never be identically zero.

Hello,
I thought that lambda was a parameter. Here you seem to describe it's definitive value (as an absolute), is that correct?

I will check out the paper you sited above, 'Gravitation and Inertia'.

cc

mkirkpatrick · **Can a river be less than Quark-Deep! -** 10-30-2005, 11:58 PM

What exactly is a cosological-constant,and is it forever constant,or is it just a
temporal stand in,until we invent another word for it that gets accepted by main
stream(there that river again) science?How can all things be interconnected
(which they most certainly are)communicate with each other!Unless there is a
medium to do so?What is it that Travels across Empty space to touch its Kin,
well nothing travels at all,as space is an illusion,there is no need to travel when
you are already There.What I am saying in a long winded fashion is,that the
constant is a fluid and we are all immersed within it and this river is less than
Half-Quark deep,so plunge in theres little fear of drowning!!!

kind regards michael.

AntonioLao · 10-31-2005, 08:01 PM

Quote:

Originally Posted by mkirkpatrick

What exactly is a cosological-constant

This constant was introduced by Eintein into his field equations of general relativity in order to describe a static universe. Later, Hubble was able to convince Einstein that in fact the universe is expanding. Therefore, Einstein considered introducing this constant as the biggest blunder he ever made in his scientific opus.

AntonioLao · **as a constant -** 10-31-2005, 08:10 PM

Quote:

Originally Posted by Coldcreation

Here you seem to describ it's definitive value

$a_i = \int \frac{1}{m_i} cE_i \Lambda dt$

None the variables or parameters within the above integral can have values of zero except lambda. When lambda is zero then the incremental acceleration is also zero.

Guille · 11-01-2005, 10:22 AM

[quote=AntonioLao] $a_i = \int \frac{1}{m_i} cE_i \Lambda dt$ [quote]

What is the symbol that looks like a capital letter A without the middle bar?

I ask because that is the exact same symbol used to represent lattices, which I'm now learning.