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Thread: Iron-56

  1. #21
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    Re: Iron-56

    Quote Originally Posted by Graybeard
    how do they contribute to anti-centripetal force that holds the galaxies and clusters of galaxies together
    The same way a speck of dust would contribute to the weight of a person.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  2. #22
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    Re: Iron-56

    Quote Originally Posted by AntonioLao View Post
    The same way a speck of dust would contribute to the weight of a person.
    But if they are not in the galaxies and clusters ..... but in the vacuum or void of space ..... how do they contribute, from that position, to the clustering of the cosmos

    greg
    'Blondie says I must hate all Brunettes. I'll try, but if I can't ... I'll love them both'
    ... graffiti on Tavern wall, Pompeii, circa AD 70.

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    AntonioLao (10-05-2010)

  4. #23
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    Re: Iron-56

    Actually, the existence of these L-points prevent galaxies from coming into actual physical contact, making them into a solid objects (considering the levels of discreteness, molecules, atoms, and quarks of physical reality, the idea of true solid object is questionable). My explanation for this is found in a new thread called "Lagrangian ubiquity." These L-locations can be empty or full of matter but their gravitational contributions is disjointedly localized since each point can neither push or pull any other neighboring systems away or toward them. They just dont have the strength to do so. For example, a person stuck in the middle of a large group of people.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Graybeard (10-05-2010)

  6. #24
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    Re: Iron-56

    Austin found this link.

    CLICK


    greg
    'Blondie says I must hate all Brunettes. I'll try, but if I can't ... I'll love them both'
    ... graffiti on Tavern wall, Pompeii, circa AD 70.

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    AntonioLao (10-05-2010)

  8. #25
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    Re: Iron-56

    If we keep looking we might just find what we are looking for. I'm looking for cold fusion.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

 

 
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