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disoriented forces
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disoriented forces - 05-11-2006, 02:59 PM

These forces are orthogonal forces when randomly distributed, demonstrations will be shown later...


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Re: disoriented forces - 05-11-2006, 03:09 PM

For a start, I cannot make any sense the comment by J.A. Wheeler
"Space tells mass how to move" while "mass tells space how to curve" regarding general relativity. It was also J.A. Wheeler who suggested to Feynman about electron going backward in time.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Re: disoriented forces - 05-11-2006, 03:33 PM

Can any force become a disoriented force? If so, when does that happen? When do gravity or electromagnetism become disoriented forces?
  
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Re: disoriented forces - 05-12-2006, 12:27 AM

Quote:
Originally Posted by AntonioLao
For a start, I cannot make any sense the comment by J.A. Wheeler
"Space tells mass how to move" while "mass tells space how to curve" regarding general relativity. It was also J.A. Wheeler who suggested to Feynman about electron going backward in time.
You have to think in terms of vector fields. the arrows, or derivatives of a field, describe the movement in a coordinate space. From here the first assertion.
the second comes from Newton's second law and the curvature of space as conceived by the minkowskian geometry.

As for the disoriented forces, don't seem clear to me, neither possible. you would have to specify a frame of reference.
  
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Re: disoriented forces - 05-12-2006, 12:19 PM

Quote:
Originally Posted by GUILLE
Can any force become a disoriented force? If so, when does that happen? When do gravity or electromagnetism become disoriented forces?
When the magnitudes of the forces vanish they become null vectors and although they still exist they don't interact. EM and gravity can never be disoriented. However, when they are coupled to a torque they become squares of energy. See the image below
Attachment 242


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

Last edited by AntonioLao : 01-14-2008 at 03:27 PM.
  
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Re: disoriented forces - 05-12-2006, 12:22 PM

Quote:
Originally Posted by hanzoganz
As for the disoriented forces, don't seem clear to me, neither possible. you would have to specify a frame of reference.
Thinking out of the box, I'm not limited to any frame of reference. Hence what is shown is free of coordinate patches and any vector fiber bundles.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Re: disoriented forces - 05-12-2006, 05:46 PM

Antonio,

Thanks for the information. In the image you give, there is one of the squares of energy which is formed by a different type of line pairs. What are the different types of square of energies, and in what do they deffer? Do you have a theory of how they interact (amongst themselves or with other particles)?
  
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Re: disoriented forces - 05-14-2006, 03:03 PM

Quote:
Originally Posted by GUILLE
there is one of the squares of energy which is formed by a different type of line pairs. What are the different types of square of energies, and in what do they deffer? Do you have a theory of how they interact
Before replying, I need to create some more images. So, maybe tomorrow I would have the time to make a complete response.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Re: disoriented forces - 05-15-2006, 11:42 AM

Quote:
Originally Posted by GUILLE
What are the different types of square of energies, and in what do they deffer? Do you have a theory of how they interact (amongst themselves or with other particles)?
The image below shows the two and only two basic squares of energy. The radius of the circles are minimum length such as Planck length by choice. Each could be represented by Hadamard matrix. One as H+ and the other as H-. H+ and H- interact by matrix multiplication or addition. Multiplication product gives mass while addition sum gives charge.

Attachment 243


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

Last edited by AntonioLao : 01-14-2008 at 03:27 PM.
  
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Re: disoriented forces - 05-15-2006, 01:16 PM

Quote:
Originally Posted by AntonioLao
The image below shows the two and only two basic squares of energy. The radius of the circles are minimum length such as Planck length by choice. Each could be represented by Hadamard matrix. One as H+ and the other as H-. H+ and H- interact by matrix multiplication or addition. Multiplication product gives mass while addition sum gives charge.

Attachment 243
1.Which is plus and which is minus?

2.What do the different colours of the arrows mean?
  
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