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Anti-gravity: possible but not practical
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Anti-gravity: possible but not practical - 10-05-2005, 07:21 PM

The natural frequency of earth is [Unparseable Latex Formula] hertz. This is equal to the ratio of the gravitational acceleration 9.8 m/s² divided by the escape velocity of 11,000 m/s and multiplied by [Unparseable Latex Formula] where [Unparseable Latex Formula] is the angle between the tangent and velocity vector at a point. The equation for the escape velocity as a function of angle φ is [Unparseable Latex Formula]

At the velocity of 11,000 m/s, the angle comes out to be about 89.999994904°, which is practically vertical ascent. At light speed, the angle is 89.999158476°. At angle of 0°, the absolute magnitude of the velocity vector is 4,635,792,013 times light speed.



Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

Last edited by AntonioLao : 10-06-2005 at 12:40 PM.
  
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Anti-gravity is not thrust
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Anti-gravity is not thrust - 10-06-2005, 04:27 PM

Hi Antonio;
I don't think anti-gravity has anything to do with thrust.
If you truly create anti-gravity, at the right time of day the earth would simply move away from you. I suppose you may need to overcome the inertia imposed on you by the earth's orbital velocity.

  
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10-06-2005, 09:06 PM

Dave,

frequency resonance or dissonance as the cas maybe. Once it is accomplished, the gravity force from mass is nullified (there can still be gravity from energy). This has been demonstrated by helicopter principle with the surrounding air. The same thing could be done with the surrounding vacuum. When the object is vibrating at the same fundamental frequency as the earth, their masses do not attract.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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10-07-2005, 10:21 AM

Hi Antonio;
Are you assuming the Earth has a resonant frequency that produces gravity?

Quote:
This has been demonstrated by helicopter principle with the surrounding air. The same thing could be done with the surrounding vacuum.
The helicopter principle affect by the surrounding air is influenced due to gravity. How does this relate to the concept of the surrounding vacuum or energy?

  
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10-07-2005, 12:56 PM

Dave,

In aerodynamics, Bernoulli's Princincple describes the pressure differences of air and the differences in the velocity vectors around the airfoil creating a lifting force not a thrusting force. If the vacuum is considered as a fluid then a Bernoulli's Principle of vacuum fluid dynamics would also creates a lifting force. However, in the quantum mechanics of the helicopter, we need to take into consideration all the tiny vectors that are causing the macroscopic pressure differences.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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10-07-2005, 01:32 PM

Antonio;
I see your point.
Do you know how to create this differential spatial density (pressure)?
I think you may find it relates to the cause of expansion and condensing of space or as many say, "spacetime".

  
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10-07-2005, 02:25 PM

Quote:
Originally Posted by dleviwing
Do you know how to create this differential spatial density (pressure)?
No, I don't. I wish I had taken more engineering courses or applied physics.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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vacuum displacement
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vacuum displacement - 10-09-2005, 02:24 PM

The principle of submarines is one of water displacement by air. The principle of hot air balloons is one of cold air displacement by hot air. In each of these cases, the higher density matter lifts the lower density matter away from the central gravity field. The principle of anti-gravity is then one of vacuum displacement by microscopic density variations. The technical problem then is how we control the microscopic density variations of a given volume of vacuum.

The interplanetary or interstellar region is not really a perfect vacuum in the sense devoid of matter and energy. There are always cosmic rays in term of energetic protons, tired photons of varying energies from the farthest reaches of the universe, neutrino disappearances of still unknown origins. In other words, outer space is a busy place of exotic things traveling at high velocities between sub-luminal, luminal and maybe superluminal speeds. Therefore, the microscopic density variations are not that of neutral matter or neutral atoms but of charged matter in term of plasma. The technical name for the fluid mechanics of plasma is the term magnetohydrodynamics and one of the leading authorities on this subject is Arnab Rai Choudhuri.

The hydrogen atom of 1 proton and 1 electron, although is a neutral plasma, has many orbital frequencies for quantized stable Bohr radii (in plasma dynamics, these radii are equivalent to the Larmor radii and frequencies). If these radii become bigger without causing ionization, then the atom remains neutral while its plasma density is a decrease. In a sense, the atom appears larger than normal; the space between nucleus and electron occupies a larger volume. The salient point is to make the atomic volume bigger but its mass remains constant and its electromagnetic effects shielded within the Debye length. These increases in atomic radii are at an advantage since they prevent the collisions between charged particles and avoiding the loss of energy through bremsstrahlung radiation. However, when the plasma particles become relativistic around the magnetic field, we still have to contend with synchrotron radiation.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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10-09-2005, 03:36 PM

Antonio;
I have worked in the area of high energy plasma for several years. I can assure you with certainty that you are right.

The hydrogen analogy you describe occurs with the solidification of hydrogen. This occurs for only a few picoseconds just before it produces a Big Bang. It's called a hydrogen bomb. This process has been proposed as a rocket fuel based on a series of "Little Bangs".

In a more serious note though; your concept of standing wave symmetry is one of the keys to anti-gravity. Thus far it is too inefficient to be practical.
Regards;
Dave



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10-10-2005, 04:02 PM

Quote:
Originally Posted by dleviwing
Thus far it is too inefficient to be practical.
Thanks for your encouraging comments. Would advancements in nanotechnology make it practical?


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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