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to e or not to e - 02-06-2008, 12:49 PM

To be or not to be was what Shakespeare said more than 500 years ago. Now, the most important philosophical question is to e or not to e. To e is to accept irrationality but not to e is to accept rationality.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Smile Re: to e or not to e - 02-06-2008, 01:02 PM

Quote:
Originally Posted by AntonioLao View Post
To be or not to be was what Shakespeare said more than 500 years ago. Now, the most important philosophical question is to e or not to e. To e is to accept irrationality but not to e is to accept rationality.

I think there is room for both,bit like Ying and Yang!



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Re: to e or not to e - 02-06-2008, 01:12 PM

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Originally Posted by mkirkpatrick
there is room for both,bit like Ying and Yang
Or it could be like Shakespeare's Comedy of Errors: where it is art imitating life or life imitating art? http://etext.library.adelaide.edu.au...rors/full.html


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Smile Re: to e or not to e - 02-06-2008, 01:17 PM

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Or it could be like Shakespeare's Comedy of Errors: where it is art imitating life or life imitating art? http://etext.library.adelaide.edu.au...rors/full.html

Thanks for the humorous link my friend,ahead! ahead! I see no ships,only hardships
methinks!



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Re: to e or not to e - 02-07-2008, 12:12 PM

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I see no ships,only hardships methinks
However, if you combine or equivalently multiply e and the reciprocal of e you get unity or simply 1 ship in sight ready to come ashore.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Smile Re: to e or not to e - 02-07-2008, 12:27 PM

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However, if you combine or equivalently multiply e and the reciprocal of e you get unity or simply 1 ship in sight ready to come ashore.
That's ok then,however I hope that if the ship comes ashore there is no boson
on board,as the last one I met kept winking at me and I felt very uncomfortable,
know what I mean?


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Re: to e or not to e - 02-07-2008, 12:34 PM

Quote:
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I hope that if the ship comes ashore there is no boson
on board
That is absolutely true. You see, if we take the square of a singular Hadamard matrix that is to say multiply by itself and the fact that it is a differential domain then the product is zero.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Smile Re: to e or not to e - 02-07-2008, 12:40 PM

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That is absolutely true. You see, if we take the square of a singular Hadamard matrix that is to say multiply by itself and the fact that it is a differential domain then the product is zero.

Then we are well on our way then?



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Re: to e or not to e - 02-07-2008, 12:45 PM

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Then we are well on our way then
Depending which ways? Way to zero consciousness? Or way to infinite consciousness? It seems that when we fall asleep we are going in the way of approaching zero consciousness and when we are awake we seem to move in the way of infinite consciousness. When we die which way are we going?


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Smile Re: to e or not to e - 02-07-2008, 12:51 PM

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Depending which ways? Way to zero consciousness? Or way to infinite consciousness? It seems that when we fall asleep we are going in the way of approaching zero consciousness and when we are awake we seem to move in the way of infinite consciousness. When we die which way are we going?

We are still straddling the two as when we die we are still mostly relative?The etheric
astral plane is still only relatively real,and being so is also an illusion!

The way forward in the noble middle way.


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