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  1. #1
    Raider of the lost time
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    Lorentz force is a force of the future

    Lorentz force of electromagnetism is a force of the future. The light at the end of the tunnel.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    The Thinker
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    Do you mean that all electromagnetism will eventually becom Lorenz force?

    If so, what is Lorenz force made of?

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    EM force is the same as Lorentz

    Lorentz force is the same force as electromagnetic force. It is the sum of electric force and magnetic force.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Quote Originally Posted by AntonioLao
    Lorentz force is the same force as electromagnetic force. It is the sum of electric force and magnetic force.
    I've been doing many mathematical workings which have taken me to an important discoverment towards EM being unified with Gravity throughout the electromagnetic equations and spetial relativity.

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    how about general relativity?

    Aren't you forgetting the nonlinear field equations of general relativity?
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Quote Originally Posted by AntonioLao
    Aren't you forgetting the nonlinear field equations of general relativity?
    No. But GR's math leads to complications with QM. Whiles if I do a re-unification of Maxwell and young Einstein, I could avoid older Einstein's problem with Bohr, Heisenberg and all the other quantum guys, and therefore be nearrer to a TOE.

    I've decided to adopt this method because it's easier to re-formulate one of the halfs than putting them to gether form how they are, specially if I don't want to go into illusionary theories: strings, aether...

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    Poincare group or Lorentz group?

    Are you then using the more general Poincare group instead of the usual Lorentz group? http://en.wikipedia.org/wiki/Poincare_group
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  8. #8
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    Quote Originally Posted by AntonioLao
    Are you then using the more general Poincare group instead of the usual Lorentz group? http://en.wikipedia.org/wiki/Poincare_group
    Still haven't gone on to that. But up to what I see, neither of them satisfy my math, so I wil have to develop a "Garridonian Group" which is good enough.

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    algebra

    Quote Originally Posted by GUILLE
    I wil have to develop a "Garridonian Group" which is good enough.
    Can you show me your tentative algebra? Associativity, commutativity, distributativity, identity, inversibility, etc?
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Quote Originally Posted by AntonioLao
    Can you show me your tentative algebra? Associativity, commutativity, distributativity, identity, inversibility, etc?
    I will write a paper. But I have no time neough to think much about it, for now.

 

 
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