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  1. #1
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    momentum space to face

    The different faces of momentum space http://en.wikipedia.org/wiki/Momentum_space are the key to unlocking the mystery of the whole universe. The biggest momentum space is that of the universe itself. This universal momentum space by Newton’s 3rd law of motion http://en.wikipedia.org/wiki/Newton's_laws_of_motion is set to zero leading to the law of linear momentum conservation http://en.wikipedia.org/wiki/Momentum.

    The Fermi liquid has its nonzero momentum space says equal unity while Bose liquid has its zero momentum space. Therefore mixing Fermi and Bose liquid would create a momentum space between 1 and 0. Since energy is a function of momentum, lesser momentum would indicate lesser energy within the control volume. The energy difference is released as useful energy as in cold fusion.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  2. #2
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    Smile Re: momentum space to face

    Quote Originally Posted by AntonioLao View Post
    The different faces of momentum space http://en.wikipedia.org/wiki/Momentum_space are the key to unlocking the mystery of the whole universe. The biggest momentum space is that of the universe itself. This universal momentum space by Newton’s 3rd law of motion http://en.wikipedia.org/wiki/Newton's_laws_of_motion is set to zero leading to the law of linear momentum conservation http://en.wikipedia.org/wiki/Momentum.

    The Fermi liquid has its nonzero momentum space says equal unity while Bose liquid has its zero momentum space. Therefore mixing Fermi and Bose liquid would create a momentum space between 1 and 0. Since energy is a function of momentum, lesser momentum would indicate lesser energy within the control volume. The energy difference is released as useful energy as in cold fusion.
    What would be needed to safely complete this experiment?



    regards michael
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  3. #3
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    Re: momentum space to face

    Quote Originally Posted by mkirkpatrick
    What would be needed to safely complete this experiment
    This is the same as that done in cold fusion research. The latter were not cold enough and there where no Cooper pairs.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  4. #4
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    Smile Re: momentum space to face

    Quote Originally Posted by AntonioLao View Post
    This is the same as that done in cold fusion research. The latter were not cold enough and there where no Cooper pairs.
    What then is needed to bring this down enough in coldness to activate this process?



    regards michael.
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  5. #5
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    Re: momentum space to face

    Quote Originally Posted by mkirkpatrick
    What then is needed to bring this down enough in coldness to activate this process
    If the way to create Cooper pairs is to lower temperature then by all means lower the temperature. But there must be a way to create Cooper pairs at room temperature?
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  6. #6
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    Smile Re: momentum space to face

    Quote Originally Posted by AntonioLao View Post
    If the way to create Cooper pairs is to lower temperature then by all means lower the temperature. But there must be a way to create Cooper pairs at room temperature?
    I am sure there is a way to accomplish this at room temperature,this is what I was looking
    at in the mental state of Samhedi where this can lead to fusion at room temperature,and
    the opening up of a gravity well that will permit a down flow of super-consciousness.



    regards michael.
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  7. #7
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    Re: momentum space to face

    Quote Originally Posted by mkirkpatrick
    I am sure there is a way to accomplish this at room temperature
    However, quantum vortices of half integer (fermions) become macroscopically impossible to join into double vortices of integer spin bosons due to large collision cross section and thermal agitations such that the de Broglie wavelengths are extremely small compared to collision distances.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  8. #8
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    Smile Re: momentum space to face

    Quote Originally Posted by AntonioLao View Post
    However, quantum vortices of half integer (fermions) become macroscopically impossible to join into double vortices of integer spin bosons due to large collision cross section and thermal agitations such that the de Broglie wavelengths are extremely small compared to collision distances.
    If a nuetral space of containment were supplied,this may well balance any joining
    potential,and permit the sequence to complete.



    regards michael.
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  9. #9
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    Re: momentum space to face

    Quote Originally Posted by mkirkpatrick
    If a nuetral space of containment were supplied
    Would this by any chance be the vacuum itself?
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

 

 

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