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Re: angular momentum of bosons
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Re: angular momentum of bosons - 03-15-2007, 04:00 PM

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Originally Posted by mkirkpatrick
Where there is one vortex,another is not far off.
Near and far are both meaningless according to special relativity that is when and where time and space are separated but if time and space are linked together into spacetime then near and far suggest twisted or warped space and two ways time motion into the past or into the future.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Re: angular momentum of bosons
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Smile Re: angular momentum of bosons - 03-15-2007, 04:05 PM

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Originally Posted by AntonioLao View Post
Near and far are both meaningless according to special relativity that is when and where time and space are separated but if time and space are linked together into spacetime then near and far suggest twisted or warped space and two ways time motion into the past or into the future.

That is correct,I was meaning really that spinners are rarely if ever alone!



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Re: angular momentum of bosons
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Re: angular momentum of bosons - 03-21-2007, 03:22 PM

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Originally Posted by mkirkpatrick
spinners are rarely if ever alone!
How about the movers and shakers? The pioneers of every distinctive human endeavors. The ones with gathering momentums? Maybe not angular momentum since it is quantized, it can't be added or taken away.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Re: angular momentum of bosons
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Smile Re: angular momentum of bosons - 03-21-2007, 06:36 PM

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How about the movers and shakers? The pioneers of every distinctive human endeavors. The ones with gathering momentums? Maybe not angular momentum since it is quantized, it can't be added or taken away.

We are doing our own bit of moving and shaking here?


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Re: angular momentum of bosons
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Re: angular momentum of bosons - 03-22-2007, 02:04 PM

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We are doing our own bit of moving and shaking here?
Maxwell found out long ago that energy derived from the kinetic theory of gases does not depend on how many gas particles (density and viscosity) there are but their average velocities.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Re: angular momentum of bosons
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Smile Re: angular momentum of bosons - 03-22-2007, 02:06 PM

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Maxwell found out long ago that energy derived from the kinetic theory of gases does not depend on how many gas particles (density and viscosity) there are but their average velocities.
At the moment I am full of gas!



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Re: angular momentum of bosons - 03-22-2007, 02:21 PM

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At the moment I am full of gas!
Liked Maxwell said it is the average speed of the gas that counts not how much of it.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Re: angular momentum of bosons
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Smile Re: angular momentum of bosons - 03-22-2007, 03:25 PM

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Liked Maxwell said it is the average speed of the gas that counts not how much of it.

Speed is of utmost importance if one is to escape the gas cloud?



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Re: angular momentum of bosons
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Re: angular momentum of bosons - 03-23-2007, 01:02 PM

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Speed is of utmost importance if one is to escape the gas cloud?
Statistically, only the average speed can be measured. If I'm not mistaken, the distribution of these speeds is known as the Maxwell- Boltzmann distribution. See http://en.wikipedia.org/wiki/Maxwell...n_distribution


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Re: angular momentum of bosons
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Smile Re: angular momentum of bosons - 03-23-2007, 07:01 PM

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Statistically, only the average speed can be measured. If I'm not mistaken, the distribution of these speeds is known as the Maxwell- Boltzmann distribution. See http://en.wikipedia.org/wiki/Maxwell...n_distribution
Thats the gas sorted,now back to bosons and their vector flexings.




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