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die proton die - 03-20-2007, 12:41 PM

Most people involved in the search for proton decay wanted to see a proton die a natural death. So far, they were disappointed. Why proton refuses to die remains a great mystery, to them. They accepted theories predicting that heavier mass particles should eventually decay into lighter ones. Since the quarks inside a proton are heavier than all their lepton’s counterparts they must decay into them. But this belief relies on a classical concept of mass. A relativistic concept of mass suggests otherwise.

Classical mass is based on a Newtonian definition that density is the ratio of mass over the 3D space volume occupied. However, relativistic volume must be expressed in 3D space and time. Since the direction of relativistic time is invariance heavier mass implies a time direction backward to the big bang singularity. Furthermore, relativistic length contraction also support heavier mass as the relativistic volume shrinks to zero. The key ingredient for these relativistic effects is the existence of light speed components inside the quark constituents of the proton. These components disguise the absolute angular acceleration of the repulsive primary superforce. See http://en.wikipedia.org/wiki/Proton_decay


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Smile Re: die proton die - 03-20-2007, 01:09 PM

Prehaps the reason they do not die is because energy is eternal,all that can happen
is change or transmuting,but not death.

regards michael.


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Re: die proton die - 03-20-2007, 01:26 PM

Quote:
Originally Posted by mkirkpatrick
the reason they do not die is because energy is eternal
Good explanations could only come from applying the principle of relativity for time dilation and length contraction. What I think is that square of energy is eternal while first power of energy is the link between eternal square of energy and matter as we know them.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Smile Re: die proton die - 03-20-2007, 01:33 PM

Are you here implying and outer (relative)energy,and an inner (absolute) energy?

regards michael.


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Re: die proton die - 03-20-2007, 01:56 PM

An outer flowing continuous space as product of light speed and first power of energy. The other is an infinitesimal local (inner) motion of quantized space as squares of energy. The ratio of quantized space (H) over the continuous space (S) is a new definition for linear momentum (p): p = H/S. The integral of p over the entire universe is exactly zero which implies that quantized space is dual of H+ and H-. These Hadamard matrices solve both mass and charge renormalization.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Smile 03-20-2007, 02:09 PM

There is a pair of dual twisters in here somewhere! Y+Y=C!

regards michael.


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03-20-2007, 02:19 PM

My translation would be particles and fields. See http://www.rwc.uc.edu/koehler/qg/pf.html


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

Last edited by dleviwing : 03-22-2007 at 01:32 PM.
  
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Smile Re: die proton die - 03-21-2007, 01:13 PM

Great link thanks,what we need is to find the MONO-Particle that opens up all
the field,so that we are on an even plane?

regards michael.


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Re: die proton die - 03-21-2007, 01:18 PM

Quote:
Originally Posted by mkirkpatrick
the MONO-Particle that opens up all the field
Thanks for mentioning this. I didn't read the whole webpage. So, I will go back and read it more carefully the next time.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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Smile Re: die proton die - 03-21-2007, 01:23 PM

Quote:
Originally Posted by AntonioLao View Post
Thanks for mentioning this. I didn't read the whole webpage. So, I will go back and read it more carefully the next time.

The MONo-particle was not on the webpage,that is my idea!



regards michael.


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