light speed as deltas of potentials

[AntonioLao]

the speed of light is really derived from the time rate change of the scalar potential and the vector potential of classical electrodynamics.

[math] c=\frac{1}{\sqrt{\mu_0 \epsilon_0}}[/math]

where [math]\mu_0[/math] is the permeability of the vacuum and [math]\epsilon_0[/math] is the permittivity of the vacuum.

But if gravity equals zero, then the speed of something is equal to the ratio of the electric field (E) over the magnetic field (B).

[math] v=\frac{E}{B}[/math]

[Guille]

So we could say d/t=e/b

(distance/time=v (speed)=electric field/magnetic field)?

[AntonioLao]

So we could say d/t=e/b

(distance/time=v (speed)=electric field/magnetic field)?

if and only if the force of gravity=0.

[math]G\frac{m_1 m_2}{r^2}= ma=0[/math]