[Guille]

Originally Posted by AntonioLao

what are the e upside down? then I will knwo it all.

[AntonioLao]

Originally Posted by GUILLE

what are the e upside down?

they are partial derivatives of differential calculus. So that a derivative with respect to the x axis will treat the y and z axis as constants.

[Guille]

Originally Posted by AntonioLao

they are partial derivatives of differential calculus. So that a derivative with respect to the x axis will treat the y and z axis as constants.

Now I get it. what is then the letter and equation used in circular momentum? did ou give it to me in the momentum vs. inertia thread?

[AntonioLao]

Originally Posted by GUILLE

what is then the letter and equation used in circular momentum?

angular momentum (L) is defined as the outer (cross or vector) product of linear momentum (p) and distance (r).



and this kind of product is not commutative.

[Guille]

Originally Posted by AntonioLao

angular momentum (L) is defined as the outer (cross or vector) product of linear momentum (p) and distance (r).



and this kind of product is not commutative.

is there a ¿¿why?? for this not being commutative?

[AntonioLao]

Originally Posted by GUILLE

is there a ¿¿why?? for this not being commutative?

Ordinarily, by convention, the cross products of vectors use the right-handed rules of coordinate axes. But the left-handed system is just as good and it does exist, physically speaking. So by mirror reflections, the right-handed system is transformed into the left-handed system.

[Guille]

Originally Posted by AntonioLao

outer (cross or vector) product of linear momentum (p)

What is the outer product of linear momentum?

[AntonioLao]

Originally Posted by GUILLE

What is the outer product of linear momentum?

the outer product of linear momentum with length is angular momentum.
the outer product of linear momentum with velocity is some kind of kinetic energy but kinetic energy is a scalar quantity therefore the outer product must be the gradient of kinetic energy.

[Guille]

Originally Posted by AntonioLao

the outer product of linear momentum with length is angular momentum.
the outer product of linear momentum with velocity is some kind of kinetic energy but kinetic energy is a scalar quantity therefore the outer product must be the gradient of kinetic energy.

but doesnt that mean that angular momentum times time equal kinetic energy?

[AntonioLao]

Originally Posted by GUILLE

angular momentum times time equal

angular momentum times time equals the product of mass and area, which is linear mass density for the outward flux of a control volume for an isolated system.