The implication is that practice makes perfect or the more the merrier.Originally Posted by mkirkpatrick
The implication is that practice makes perfect or the more the merrier.Originally Posted by mkirkpatrick
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
Another question here is,will the full potential of form be realized,and what will that then be like?Prehaps this will bring about fusion at room temperature!
regards michael.
Humilty,coupled with boldness,surprises truth to
reveal herself?
lose track of this thread. Sorry, could not immediately reply.Originally Posted by mkirkpatrick
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
Only if I needed to do mountain climbing in the Himalayas. I'm still having trouble with form and potential, especially, the form structure of quantum space-time and the vector potential of electromagnetism.thinking of hiring a Sherpa?
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
Physically or mathematically? I am still having problem visualizing the mathematical object of a vector potential of magnetic origin.Originally Posted by mkirkpatrick
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
Scientifically, there are two distinct energy potentials: the scalar and the vector. Where the gradient of the scalar potential is a force but the vector potential is already a force. Magnetic potential falls in the latter category. Yet magnetic monopole cannot be detected.Originally Posted by mkirkpatrick
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
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