ToeQuest

We're going on a TOE Quest!


Register

Reply

Raider of the lost time

AntonioLao's Avatar

Join Date: Nov 2003
Posts: 6,036
Blog Entries: 6
86 AntonioLao is a splendid one to beholdAntonioLao is a splendid one to beholdAntonioLao is a splendid one to beholdAntonioLao is a splendid one to behold
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Spurl this Post!Reddit!
Quote  
03-13-2006, 03:22 PM
squaring circularly

Ancient Greek geometers and mathematicians were able to construct a square equal in area to any given parallelogram or quadrilateral. However, they failed to find a square with sides of s = 1 such that s = p. Nevertheless p represents an angular measurement that of a straight line segment and 1 represents the quantum of unit length of measurement.
__________________
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
Reply With Quote
AntonioLao is offlineReport Post
4th degree Black Belt

baudrunner's Avatar

Join Date: Dec 2005
Posts: 587
Blog Entries: 6
18 baudrunner is a jewel in the rough
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Spurl this Post!Reddit!
Quote  
03-13-2006, 04:43 PM
I am not really acquainted directly with the issue here but it seems that there is no real solution regardless whatever the linear angular measurement where it is no greater than 1 because the result provides that the p·p is always too small. It is expressed as a unitary problem and is non-utilitarian in any event.
__________________
"There is nothing permanent except change"
Reply With Quote
baudrunner is offlineReport Post
Raider of the lost time

AntonioLao's Avatar

Join Date: Nov 2003
Posts: 6,036
Blog Entries: 6
86 AntonioLao is a splendid one to beholdAntonioLao is a splendid one to beholdAntonioLao is a splendid one to beholdAntonioLao is a splendid one to behold
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Spurl this Post!Reddit!
Quote  
03-14-2006, 01:02 PM
The point I'm trying to make is the distinction for length and angle measurement. This couldn't have been more distinctively crucial for some descriptive analyses than when at the local infinitesimal region of space-time quantization: quantum of length and quantum of phase angle.
__________________
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
Reply With Quote
AntonioLao is offlineReport Post
Reply

Currently Active Users Viewing This Thread: 1 (0 members and 1 guests)
 
Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On
Forum Jump

Similar Threads
Thread Thread Starter Forum Replies Last Post
squaring Lorentz force AntonioLao Mathematics 12 02-21-2006 01:00 PM



All times are GMT -4. The time now is 10:22 PM. Powered by vBulletin® Version 3.7.4
Copyright ©2000 - 2008, Jelsoft Enterprises Ltd.
Content Relevant URLs by vBSEO 3.2.0 VBulletin Skin by ForumMonkeys.