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Raider of the lost time

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04-27-2006, 01:25 PM
before, now, or after

The trouble with any quantum field theory of infinite degrees of freedom is the free will of two observable related quantum states making the appropriate choice when to connect and when to disconnect. This choice is the equivalent to the quantum mechanical processes of localizing or nonlocalizing the associated standing waves y(a) and y(b). However, the most energy cost effective Lagrangian (kinetic energy minus potential energy) is to remove all extraneous energy deficit Feynman’s path integrals of nonlocality. This can be done by applying Dirac’s delta function such that the joint standing wave y(a,b) = exp{i[q(a) + q(b)]}y(a,b) = 0 if ab and y(a,b) = 1 if a = b. This is independent of the values of the phase factors exp{i[q(a) + q(b)]} where q(a) and q(b) are the corresponding one to one phase angles. It can be demonstrated that this process localizes y(a,b) within a specified Hadamard space of only six degrees of freedom in accordance with the requirements for three dimensional electromagnetism.
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Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
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04-27-2006, 01:31 PM
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Originally Posted by AntonioLao
However, the most energy cost effective Lagrangian (kinetic energy minus potential energy) is to remove all extraneous energy deficit Feynman’s path integrals of nonlocality.


What is extraneous energy? Please explain also what the sentence means as a whole.

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three dimensional electromagnetism.
Has this been mathematically proven (if so, can you explain how)?
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Raider of the lost time

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04-27-2006, 01:45 PM
radiation pressure

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Originally Posted by GUILLE
What is extraneous energy? Please explain also what the sentence means as a whole.
Extraneous energy is excess energy or wasteful energy or any type of energy that increases entropy. As a whole, the statement reaffirmed the 1/3 characteristic of radiation pressure please see the following links
http://en.wikipedia.org/wiki/Radiation_pressure
http://scienceworld.wolfram.com/physics/RadiationPressure.html
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Originally Posted by GUILLE
Has this been mathematically proven
It is proven only if the time parameter is removed from all equaltions. However, if these are inequalities then they are implicitly time independence.
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Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
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