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  1. #1
    Raider of the lost time AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold
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    to eternity and back

    Within a global coordinate patch where the 2D gravitational potential is practically zero, a point starting at the origin moving toward positive infinity along the surface of a one-sided Moebius strip, will find itself traveling back to the origin via negative infinity. Vice versa, a point, again, starting at the origin traveling toward negative infinity will find itself back to the origin via positive infinity. These distinctions are possible if and only if a unit circle is centered at the origin with fixed counterclockwise or clockwise rotation. See the images below.

    Attachment 239

    Attachment 240
    Last edited by AntonioLao; 01-14-2008 at 04:27 PM.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  2. #2
    Raider of the lost time AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold
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    Re: to eternity and back

    At the local infinitesimal domain of space-time, the tetrads of the vector fiber bundles form two distinct topological structures given by a set of pair of polar functions which represent unit circles. These could be used to describe the directional invariance of two distinct local infinitesimal motions shown by the image below:

    Attachment 241
    Last edited by AntonioLao; 01-14-2008 at 04:27 PM.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  3. #3
    Raider of the lost time AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold
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    Re: to eternity and back

    These local infinitesimal motions could also be used to define local absolute accelerations a. Their inner product with the vector metric r is a constant square of lightspeed [math]\mathbf{a}\cdot\mathbf{r}=c^2[/math].
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  4. #4
    The Thinker Guille is a glorious beacon of light Guille is a glorious beacon of light
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    Re: to eternity and back

    Antonio,

    Your view of how the entities (space, time, matter, force, energy...) interact is very interesting. One thing I wonder: what determines the size of the circle in the graphs?

  5. #5
    6th degree Black Belt harmonygirl will become famous soon enough
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    Cool Re: to eternity and back

    Antonio, do these indicate a tendancy towards balance?
    The first is only interesting if it is the beginning of something. The first is not interesting if it is the only - Djanet Sears

  6. #6
    Green Belt pagan3142 is on a distinguished road
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    Re: to eternity and back

    So what exactly is your point ?
    We all know the properties of a Moebus. Going round in circles are we ???
    Steve . W here has all the time gone ? Your Time is my Spacetime.

  7. #7
    Raider of the lost time AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold
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    Re: to eternity and back

    Quote Originally Posted by GUILLE
    what determines the size of the circle in the graphs?
    The local infinitesimal orthogonal forces. Their existence is suppressed by general relativity.
    Quote Originally Posted by harmonygirl
    do these indicate a tendancy towards balance?
    tending to balance the orthogonal forces at the local infinitesimal level of space-time.
    Quote Originally Posted by pagan3142
    So what exactly is your point ?
    To find the orthogonal forces at the local infinitesimal region of space-time using the concept of absolute local infinitesimal accelerations.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²


 

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