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Raider of the lost time
Join Date: Nov 2003 Posts: 6,036
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05-23-2006, 01:24 PM
| | eccentric probability
For 3 of the 4 conics, the eccentricity is less than or equal to unity. In the theory of probability, unity represents absolute certainty while less than unity represents certain probability and zero represents impossibility.
Therefore, the parabolas represent certainty of classical Newtonian mechanics. Ellipses represent uncertainty of quantum mechanics. Circles represent the impossibility of detecting the true vacuum even though its existence is a theoretical certainty.
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Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
| | | | The Thinker
Join Date: Mar 2005 Posts: 3,278
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05-23-2006, 05:53 PM
| | Re: eccentric probability
Continuing the analysis, what to hyperbolas represent?
Also, what is the probability of the eccentricities? What I mean by this question is that if, for example, it is more probable (there are more possibilities) to get a parabola or an elipsis than a perfect circle? | | | | 4th degree Black Belt
Join Date: Feb 2006 Posts: 501
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05-24-2006, 11:27 AM
| | Re: eccentric probability
Antonio,
But Ellipses have a probability to be a circle. As I have studied it is said Circle is a special case of an Ellipse. But then if one of the probability of an Ellipse is to be a circle then how can the circle be impossible.
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Anything for Everyone! | | | | Raider of the lost time
Join Date: Nov 2003 Posts: 6,036
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05-25-2006, 06:40 PM
| | Re: eccentric probability
Quote: |
Originally Posted by GUILLE Continuing the analysis, what to hyperbolas represent? | I don't know. According to probability theory, no probability is greater than unity. Maybe, it's related to the probable existence of hyperspacetime, for example, from general relativity. Quote: |
Originally Posted by GUILLE what is the probability of the eccentricities? | I have no idea. Quote: |
Originally Posted by Mohan.C But Ellipses have a probability to be a circle. | That's not my argument.
__________________
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
| | | | The Thinker
Join Date: Mar 2005 Posts: 3,278
48 | |
05-26-2006, 06:29 PM
| | Re: eccentric probability
Quote: |
Originally Posted by AntonioLao I don't know. According to probability theory, no probability is greater than unity. Maybe, it's related to the probable existence of hyperspacetime, for example, from general relativity. | In your starter you say 'in 3 of the 4 conics the eccentricity is equal or less than 1'. So, do you think that there is a necessary incoerence between geometry and probability, or that they can live together (I still think their union, as I said months ago, shoul dbe the main task of mathematicians and mathematical physicists). | | | | Raider of the lost time
Join Date: Nov 2003 Posts: 6,036
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05-31-2006, 04:12 PM
| | Re: eccentric probability
Quote: |
Originally Posted by Guille that there is a necessary incoerence between geometry and probability | Geometry deals with static deterministic variables (points, lines, curves, and surfaces in topology). On the other hand, probability deals with dynamic random variables.
__________________
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
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