Erm..... I don't understand the maths part too well, which is probably why I found the article useful as it explains the concepts behind the mathematical processes!
What I would say is that where there are 3 bits, and they can both only have the value of 1 or 0, then the probability of them taking any value would be the same for 101, 110 and 111. HOWEVER.... if my understanding of probabilities is as flawed as my understanding of calculus, then there is a high probability that I am probably wrong!
DG
PS - just looked at the article again and you (and thus me!) are definately right.
