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  1. #1
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    no-step reversible process

    Combining all high probability fusion reactions in a no-step or at most 1-step reversible process would surely indicate that the origin of thermonuclear fusion, whether hot or cold, is just the joining of deuterons.

    A combination of the following irreversible reactions: (1) D + T ® He + n + energy,
    (2) D + He ® He + p + energy, (3) D + D ® He + n + energy, (4) D + D ® T + p + energy, and (5) D + D ® He + energy, gives 8D + T + He ® 2He + 2He + T + 2n + 2p + energy.

    For reversible (palindrome: step on no pets) processes: 2n + 2p « 2D then using valid algebraic eliminations of components on the right-hand side and left-hand side gives: 6D « He + 2He + energy. Theoretically, this reversible nuclear reaction suggests that fusion of deuterons gives two distinct superfluids plus positive energy. The superfluids are the Fermi liquid: He and the Bose Liquid: He. Both are isotopes of helium. This has a production ratio of 2 to 1 in favor of the Bose liquid.

    The symmetry of this particular reaction also suggests the existence of negative energy by the inverse reaction: 6D - energy « He + 2He. This shows that fusing deuterons with negative energy gives naturally the two and only two superfluids ever found by low temperature physicists.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  2. #2
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    Smile Re: no-step reversible process

    Quote Originally Posted by AntonioLao View Post
    Combining all high probability fusion reactions in a no-step or at most 1-step reversible process would surely indicate that the origin of thermonuclear fusion, whether hot or cold, is just the joining of deuterons.

    A combination of the following irreversible reactions: (1) D + T ® He + n + energy,
    (2) D + He ® He + p + energy, (3) D + D ® He + n + energy, (4) D + D ® T + p + energy, and (5) D + D ® He + energy, gives 8D + T + He ® 2He + 2He + T + 2n + 2p + energy.

    For reversible (palindrome: step on no pets) processes: 2n + 2p « 2D then using valid algebraic eliminations of components on the right-hand side and left-hand side gives: 6D « He + 2He + energy. Theoretically, this reversible nuclear reaction suggests that fusion of deuterons gives two distinct superfluids plus positive energy. The superfluids are the Fermi liquid: He and the Bose Liquid: He. Both are isotopes of helium. This has a production ratio of 2 to 1 in favor of the Bose liquid.

    The symmetry of this particular reaction also suggests the existence of negative energy by the inverse reaction: 6D - energy « He + 2He. This shows that fusing deuterons with negative energy gives naturally the two and only two superfluids ever found by low temperature physicists.
    I feel that there is significant reason for his,could there possibly be though an implied
    third?
    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  3. #3
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    Re: no-step reversible process

    Quote Originally Posted by mkirkpatrick
    could there possibly be though an implied third?
    The implied third would be analogous to the lambda point where solid, liquid, and gas coexist.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Smile Re: no-step reversible process

    Quote Originally Posted by AntonioLao View Post
    The implied third would be analogous to the lambda point where solid, liquid, and gas coexist.
    Absolutely,a point in which exchange can occur,without robbery?




    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  5. #5
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    Re: no-step reversible process

    Quote Originally Posted by mkirkpatrick
    a point in which exchange can occur
    In a system at thermodynamic equilibrium, rate of emission equals rate of absorption of energy.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  6. #6
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    Smile Re: no-step reversible process

    Quote Originally Posted by AntonioLao View Post
    In a system at thermodynamic equilibrium, rate of emission equals rate of absorption of energy.
    So in effect,there is no spin-off surplus.



    regardsmichael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  7. #7
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    Re: no-step reversible process

    Quote Originally Posted by mkirkpatrick
    So in effect,there is no spin-off surplus.
    Equilibrium systems are much idealized systems. In reality, most systems are far from thermodynamic equilibriums. They are described practically at the edges of chaos and order and are known as nonlinear systems of complexity theory.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  8. #8
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    Smile Re: no-step reversible process

    Quote Originally Posted by AntonioLao View Post
    Equilibrium systems are much idealized systems. In reality, most systems are far from thermodynamic equilibriums. They are described practically at the edges of chaos and order and are known as nonlinear systems of complexity theory.

    That is neatly described,I thank you.nature is most often the very embodiment of economy.



    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  9. #9
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    Re: no-step reversible process

    Quote Originally Posted by mkirkpatrick
    nature is most often the very embodiment of economy
    Nature uses nonlinear mathematics are so far these are not solvable but only at a few special cases.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  10. #10
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    Smile Re: no-step reversible process

    Quote Originally Posted by AntonioLao View Post
    Nature uses nonlinear mathematics are so far these are not solvable but only at a few special cases.
    Why then do we not follow this example?



    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

 

 
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