| Raider of the lost time
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Join Date: Nov 2003 Rep Power: 74 | zero freedom -
04-02-2007, 12:46 PM
Does a physical system exist that is described by a zero degree of freedom (dof)? It can be stated without proofs that all scalar physical quantities can be used to describe systems with no dof, for example: temperature, density, mass, volume, and energy. On the other hand, force, momentum, and positions all have nonzero dof called vectors. They can still lose their freedom if and only if they met others equal magnitude but exactly opposite direction. In this sense, nonzero dof implies motion while zero dof implies a state of no motion or zero freedom.
However, it is not settled by current scientific inquiries whether the physical quantity called time has zero dof or infinite dof? In fact, as an abstract arrow, time could signify increasing entropy in one dof. When the spatial dimension is restricted to one even gravity has one dof. Electric charge has exactly two dof’s. Color charge has exactly three dof’s. Zero freedom of color charge exists in two distinct states: (1) as baryons or as (2) mesons. Baryons and mesons are all colorless, which means the gauges add to zero. For example: Y(½,½,½), R(½,½,-½), G*(½,-½,½), B*(-½,½,½),Y*(-½,-½,-½), R*(-½,-½,½), G(-½,½,-½), B(½,-½,-½) and where Y*Y(0,0,0), R*R(0,0,0), G*G(0,0,0), B*B(0,0,0), G*R(1,0,0), B*R(0,1,0), B*G*(0,0,1), R*G(-1,0,0), R*B(0,-1,0), BG(0,0,-1). These give the eight gluons needed for colored quarks. For the gauges: A(½,½), B(½,-½), B*(-½,½), A*(-½,-½), where AB(1,0), A*B*(-1,0), A*A(0,0), B*B(0,0) give the intermediate vector bosons: W±, and Z°.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
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Re: zero freedom -
04-02-2007, 05:46 PM
Linear Mode
