In the natural world, there are far more binary operators than unary, tertiary, or quaternary. The word pentanary could be used to signify operations with exactly five operands. As strange as it may seems, when considering the first 4 regular polygons of equilateral triangle, square, pentagon, and hexagon, only the pentagon has its number of sides equal to its number of diagonals. The regular triangle has 3 sides but no diagonals. The square has 4 sides with 2 diagonals. The pentagon has 5 sides and also 5 diagonals. The hexagon has 6 sides but 9 diagonals. The heptagon has 7 sides and 14 diagonals, etc. The formula for finding the number of diagonals for any polygon is n(n-3)/2 where n is the number of sides.
If the diagonals of a polygon signify inner connections and the sides signify outer connections then it is clear that only the pentagon has a perfect balance between its inner and outer space connections. The great Renaissance man Leonardo da Vinci himself had noted the power of the pentanary connection and he used this to represent his famous Vitruvian Man painting http://en.wikipedia.org/wiki/Vitruvian_Man. Therefore, it can be hypothesized that a complete connection for inner space is 5 binary connections and the same number for complete outer space connection.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
Antonio,this is a most profound connection you have made here,the pentagon,5 binary
connections inner,and 5 binary connections outer,this represents the perfect number
which is 10,but it is drawn as a one,enclosed within a circle,exactly like the one you
did for me a while back,which was for another thread,A blue circle,with a red 1 within it.
regards michael.
Humilty,coupled with boldness,surprises truth to
reveal herself?
If we do that, the pentagons oriented in 3D would form a dodecahedron http://en.wikipedia.org/wiki/Dodecahedron. I more interested in controlling the magnetic field intensities and configurations. For these, it is necessary to artificially create sheet atoms beyond the transuranic elements.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
Re: binary casualty -
04-16-2007, 05:48 PM
Linear Mode
