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cold quark fusion - 04-18-2007, 03:30 PM

The nuclear reaction for cold fusion is D+D®He+energy. In term of quarks: uud+uud+udd+udd®6u6d+energy. The gauge matrix for up quark is (5,1). The 5 is the alpha entry and the 1 is the beta entry of (a,b). The gauge matrix for down quark is (3,1). Therefore, helium 4 in terms of these matrices becomes 6(5,1)+6(3,1) or (30,6)+(18,6)=(48,12). Since the beta entry is not divisible by 8, helium 4 naturally appears in the gaseous state as 2(48,12) or (96,24). Transferring these double entries into the reaction, it becomes 2D+2D®2He+twice the output energy. This indicates that cold quark fusion needs four deuterons and suggests that the plasma particles of the Bose liquid must be exact multiples of 4 deuterons as a minimum requirement for fusion to occur. This means that the magnetic field configuration is that of quadrupole magnetic moments instead of the usual dipole moments. Pentapole, hexapole, heptapole, octapole and higher moments could also possibly establish stable configurations. Similar configurations have been implemented successfully in Penning traps http://en.wikipedia.org/wiki/Penning_trap.


Time independence: [∂E(g)]˛=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c˛
  
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Re: cold quark fusion - 04-18-2007, 04:04 PM

Antonio, do you think quarks are small enough to qualify for a fundamental photonic substance___only? IYO, is the fundamental photonic substance, even smaller, or what do you think is the minimal sized particle, nearing the infinitesimal?

Lloyd

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The nuclear reaction for cold fusion is D+D®He+energy. In term of quarks: uud+uud+udd+udd®6u6d+energy. The gauge matrix for up quark is (5,1). The 5 is the alpha entry and the 1 is the beta entry of (a,b). The gauge matrix for down quark is (3,1). Therefore, helium 4 in terms of these matrices becomes 6(5,1)+6(3,1) or (30,6)+(18,6)=(48,12). Since the beta entry is not divisible by 8, helium 4 naturally appears in the gaseous state as 2(48,12) or (96,24). Transferring these double entries into the reaction, it becomes 2D+2D®2He+twice the output energy. This indicates that cold quark fusion needs four deuterons and suggests that the plasma particles of the Bose liquid must be exact multiples of 4 deuterons as a minimum requirement for fusion to occur. This means that the magnetic field configuration is that of quadrupole magnetic moments instead of the usual dipole moments. Pentapole, hexapole, heptapole, octapole and higher moments could also possibly establish stable configurations. Similar configurations have been implemented successfully in Penning traps http://en.wikipedia.org/wiki/Penning_trap.


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Re: cold quark fusion - 04-18-2007, 04:09 PM

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Originally Posted by Lloyd Gillespie
what do you think is the minimal sized particle, nearing the infinitesimal?
If it is not the photon then it must be the neutrino. Both seem to travel at lightspeed.


Time independence: [∂E(g)]˛=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c˛
  
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Smile Re: cold quark fusion - 04-18-2007, 08:00 PM

We all want fusion,whether it be cold quark or otherwise,looking at the word fusion,
blending-or uniting of different things into a whole,then look at the word synthesis,combining of seperate parts or elements to form a complex whole,there is little
difference in the two words.

Nature,naturally and within cyclic rhythm,produces both fusion and synthesis,all without
the aid of a machine?

We are a living laboratory,and can experiment within ourselves,I totally believe that
fusion can be achieved within the human being,at room temperature,and with no harm
what so ever to the individual involved.This can be accomplished by the person attaining
and maintaining a state of Samhadi,now as to extracting energy from this state that could be used to run a factory or two,well thats another story!


regards michael.


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Re: cold quark fusion - 04-23-2007, 03:51 PM

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well thats another story
That's the story that I have always wanted to hear. If you happen to know of someone selling tickets to this lecture please do let me know. I'm afraid it would be soldout for the first 5 seconds of its announcement.


Time independence: [∂E(g)]˛=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c˛
  
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Smile Re: cold quark fusion - 04-23-2007, 05:34 PM

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That's the story that I have always wanted to hear. If you happen to know of someone selling tickets to this lecture please do let me know. I'm afraid it would be soldout for the first 5 seconds of its announcement.

I will keep a sharp look out for that opportunity when it arises.


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