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  1. #1
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    up down tessellation

    The nuclei of helium 4 in term of quarks are each composed of exactly three up quarks and three down quarks. If the ups and downs are placed around alternately on the vertices of a hexagon then hexagonal tiling can be constructed in 2D space showing 6-fold symmetries.

    If quark freedom is possible, these tiling are extended into macroscopic region then nuclear sheets are formed. If electrons are then doped into both sides of these sheets then massive sheet atoms emerged. If these atomic sheets are rolled into cylindrical tubes then by simply tightening or loosening, the magnetic domains are altered on demand. Consequently, the magnetic field intensity and configuration are varied according to one’s specifications.

    Tiling of 12 regular pentagons can only result in forming a convex polyhedron as one of the five Platonic solids called a dodecahedron http://en.wikipedia.org/wiki/Dodecahedron. Up and down alternate distribution among the 20 vertices will fail to form electric charge invariance. There are 6 holes which could hold various charge configurations: 6⅓, 5⅓, 4⅓, 3⅓, 2⅓, 1⅓, ⅓; if these charges are replaced by quantum spins, interesting configurations could be seen leading to spontaneous broken spin symmetry.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  2. #2
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    Smile Re: up down tessellation

    Quote Originally Posted by AntonioLao View Post
    The nuclei of helium 4 in term of quarks are each composed of exactly three up quarks and three down quarks. If the ups and downs are placed around alternately on the vertices of a hexagon then hexagonal tiling can be constructed in 2D space showing 6-fold symmetries.

    If quark freedom is possible, these tiling are extended into macroscopic region then nuclear sheets are formed. If electrons are then doped into both sides of these sheets then massive sheet atoms emerged. If these atomic sheets are rolled into cylindrical tubes then by simply tightening or loosening, the magnetic domains are altered on demand. Consequently, the magnetic field intensity and configuration are varied according to one’s specifications.

    Tiling of 12 regular pentagons can only result in forming a convex polyhedron as one of the five Platonic solids called a dodecahedron http://en.wikipedia.org/wiki/Dodecahedron. Up and down alternate distribution among the 20 vertices will fail to form electric charge invariance. There are 6 holes which could hold various charge configurations: 6⅓, 5⅓, 4⅓, 3⅓, 2⅓, 1⅓, ⅓; if these charges are replaced by quantum spins, interesting configurations could be seen leading to spontaneous broken spin symmetry.

    If spontaneous broken symmetry could be achieved and regulated/controlled,then are
    you saying that this will lead to fusion at room temperature?


    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  3. #3
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    Re: up down tessellation

    any way you could draw that? im haveing trouble picturing it

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    Re: up down tessellation

    Quote Originally Posted by mkirkpatrick
    If spontaneous broken symmetry could be achieved
    On the contrary, we need to prevent it from happening. Avoiding the formation of mass and keep the field in pure energy form as a perfect symmetry.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  5. #5
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    Smile Re: up down tessellation

    Quote Originally Posted by AntonioLao View Post
    On the contrary, we need to prevent it from happening. Avoiding the formation of mass and keep the field in pure energy form as a perfect symmetry.
    Absolutely, how silly of me to have it this way,we don't want to blow up
    the lab!


    regards michael.
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  6. #6
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    Re: up down tessellation

    Quote Originally Posted by mkirkpatrick
    we don't want to blow upthe lab!
    I am wondering if Roger Penrose could use his tiling algorithm to tessellate regular pentagons in 3-space?
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  7. #7
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    Smile Re: up down tessellation

    Quote Originally Posted by AntonioLao View Post
    I am wondering if Roger Penrose could use his tiling algorithm to tessellate regular pentagons in 3-space?
    Thats an interesting question Antonio,shall you ask him or I ?




    regards michael.
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  8. #8
    Raider of the lost time
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    Re: up down tessellation

    Quote Originally Posted by mkirkpatrick
    shall you ask him or I
    Since you are closer space-time wise, it is more advantageous for you to ask him.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  9. #9
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    Smile Re: up down tessellation

    Quote Originally Posted by AntonioLao View Post
    Since you are closer space-time wise, it is more advantageous for you to ask him.

    I will give it a try,but suggest you do not hold you breath,awaiting a reply!



    regards michael
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    reveal herself?

  10. #10
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    Re: up down tessellation

    Quote Originally Posted by mkirkpatrick
    suggest you do not hold you breath
    Only holding it underwater, in air only behind a passing bus.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

 

 
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