| where when minus one?
Starting from a single imaginary unit, i, square it, the answer is -1. Taking the slopes of two perpendicular lines, multiply them, the result is also negative unity. These slopes exist only by a prioritized coordinate system. Insert pinto Euler’s equation the imaginary power of the base of natural logarithm becomes negative unity. The square of the product of Pauli’s second spin matrix, s-2 and the imaginary unit also gives the matrix of negative unity. In the theory of infinite series, the negative sum of the infinite sequence ½, ¼, 1/8, 1/16, 1/32, 1/64, etc. is also negative unity. Although the whole number zero separates the real numbers into pluses and minuses it is when minus unity is added to plus unity that proves zero exists (-1+1=0).
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Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
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Re: where when minus one? 
Linear Mode
