where when minus one?

[AntonioLao]

Starting from a single imaginary unit, i, square it, the answer is -1. Taking the slopes of two perpendicular lines, multiply them, the result is also negative unity. These slopes exist only by a prioritized coordinate system. Insert pinto Euler’s equation the imaginary power of the base of natural logarithm becomes negative unity. The square of the product of Pauli’s second spin matrix, s-2 and the imaginary unit also gives the matrix of negative unity. In the theory of infinite series, the negative sum of the infinite sequence ½, ¼, 1/8, 1/16, 1/32, 1/64, etc. is also negative unity. Although the whole number zero separates the real numbers into pluses and minuses it is when minus unity is added to plus unity that proves zero exists (-1+1=0).

[mkirkpatrick]

If you really minused one,you would be left with less than nothing?



regards michael.

[AntonioLao]

[QUOTE=mkirkpatrick]would be left with less than nothing[/QUOTE]
Actually a single point has dimension of -1.

[mkirkpatrick]

[QUOTE=mkirkpatrick]would be left with less than nothing

Actually a single point has dimension of -1.[/quote]

That might be the case,but what would that purchase in the real world?



regards michael.

[AntonioLao]

but what would that purchase in the real world?

This is the same as purchasing using credit cards on someone else money at borrowing interest.