It appears you have not yet registered with our community. To register please click here...

Theory of Everything  

  
Go Back   Theory of Everything > Tools > Mathematics
Reload this Page right neutrino left
Register Website Toe Club Your Blog Arcade

Welcome to the Theory of Everything forums.

You are currently viewing our boards as a guest which gives you limited access to view most discussions and access our other features. By joining our free community you will have access to post topics, communicate privately with other members (PM), respond to polls, upload content and access many other special features. Registration is fast, simple and absolutely free so please, join our community today!

If you have any problems with the registration process or your account login, please contact contact us.

Reply
 
LinkBack Thread Tools Display Modes
right neutrino left
Old
  (#1 (permalink))
Raider of the lost time
AntonioLao is a jewel in the roughAntonioLao is a jewel in the roughAntonioLao is a jewel in the roughAntonioLao is a jewel in the roughAntonioLao is a jewel in the roughAntonioLao is a jewel in the roughAntonioLao is a jewel in the rough
 
AntonioLao's Avatar
 
Status: Offline
Posts: 5,109
Thanks Given: 641
Thanked 97x in 96 Posts
Join Date: Nov 2003
Rep Power: 71
   
right neutrino left - 10-17-2007, 01:48 PM

In terms of space charges, the electron neutrino is 1H+ and 1H-. Expressed in row matrix [+1, -1] whose transpose is its column matrix. The product of row to column is a pure prime number 2, while the product of column to row is a 2 by 2 Hadamard matrix. However, if two electron neutrinos expressed as a 2 by 2 matrix then the product when multiplied by its transpose to the right is the product of prime number 2 and a 2 by 2 Hadamard matrix. The 2 serves as the neutrino multiplier. Now, if the transpose is made to operate from the left then the product is a 2 by 2 matrix with all elements having a constant integer value of positive 2.

Three neutrinos matrix multiplied with its transpose to the right give a neutrino multiplier of 3. Four neutrinos give a multiplier of 4. For five give a multiplier of 5, so on and so forth. However, if the transpose is made to operate from the left then the products are respectively, 3 by 3 of constant element 2, 4 by 4 of constant element 2, and 5 by 5 of constant element 2.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Spurl this Post!Reddit!
Reply With Quote
Reply


Currently Active Users Viewing This Thread: 1 (0 members and 1 guests)
 
Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On
Forum Jump



Powered by vBulletin® Version 3.6.8
Copyright ©2000 - 2008, Jelsoft Enterprises Ltd.
Content Relevant URLs by vBSEO 3.2.0
vBulletin Skin developed by: vBStyles.com