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During 1-millionth to 100-thousandth of a second of the hot big bang, the universe is just a dot of plasma soup of space-time quanta or charges, H+ and H-. The temperature was 10 trillions kelvins. The density was 100 trillions grams per cc. When it starts to cool quarks begin to stick together forming hadrons: baryons and mesons. If these are made up of space-time charges H+ and H- with even number conservation then there would not be any leftover space-time charges for making up gluons.
In accordance with space-time charge configuration the up quark is formed as (5,1) and the down quark is (1.3) and (5,1)+(1,3)=(6,4). The left position number in each parenthesis signifies the number of H+ and the right, the number of H-. Space-time conservation demands these numbers must be equal and multiples of even integers, for example, (4,4) or (6,6). Although these can be equalized by lepton or photon space-time charge configurations, the hadrons era is exclusively for quarks. The leptons era begins 100-thousandth second later and the photons era is a second later after the big bang. Therefore, to balance these position numbers, meson products must be introduced, for example, negative pions: (1,5)+(1,3)=(2,. Since proton is (5,1)+(5,1)+(1,3)=(11,5) and (2,+(11,5)=(13,13) which is odd multiples, neutrons: (5,1)+(1,3)+(1,3)=(7,7) must also be introduced such that (13,13)+(7,7)=(20,20) satisfies space-time charges of even conservation.
These descriptions demonstrated a revival of Yukawa’s meson theory for nuclear binding at the era of quark synthesis. These make the concept of gluons superfluous except to be used only for describing the 8 properties of directional invariance in an 86468 space-time charge configuration as required for thermonuclear fusion at much lower temperature, approaching cold fusion.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
While I read your sites I have to admit the math is so above me I can't comment.
Bob Campbell referred to my Idea as a tasty soup and I have eliminated gluons, because they weren't necessary to my theory. I have the quarks bound by superposition and interwoven. It's speculative, but I am interested is my idea POSSIBLE, not probable just POSSIBLE.
I would be very appreciative if you did that and any comments or questions you could post at my thread.
Thank you,
Pat
Last edited by Profpat : 11-15-2007 at 09:45 PM.
Reason: added a word
I will be very interested just how you accomplished gluons elimination. Since my time on this internet connection is limited to 2 hours, I must delay my review but get to it as soon as possible.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
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I will be very interested just how you accomplished gluons elimination. Since my time on this internet connection is limited to 2 hours, I must delay my review but get to it as soon as possible.
Thank you sir I would appreciate that.
Best,
Pat
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I had a quick review of your conceptual descriptions and I think you are on the right track but you probably need some mathematical supports in terms of topological spaces, Mobius and Hopf design. However, I did not locate just how you eliminated gluons?
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
I had a quick review of your conceptual descriptions and I think you are on the right track but you probably need some mathematical supports in terms of topological spaces, Mobius and Hopf design. However, I did not locate just how you eliminated gluons?
I just left them out of my Idea because I didn't need them to bind the quarks. I view the quarks are superposed and interwoven and therefore gluons are not necessary to bind them. Also I view the quarks to have their own internal colors. So I just left them out I saw no purpose for them. This is perhaps more understandable if you obtain 3 pipe cleaners and combine them as in my model.
You are correct about the math being lacking as I am an accounting professor anything beyond addition, subtraction, multiplication, and division are beyond me. I did have set theory and calculus however. But others have critized that fact also " Where is the Math " Something I obviously need help on. I did ask one member what the formula was for a Venn Diagram, but to date, no answer.
Again thank you AntonioLao
Pat
P.S. I didn't need gluons as mediators either since the quarks are attached to each other
Last edited by Profpat : 11-16-2007 at 12:58 PM.
Reason: added P.S.
[size=2] You are correct about the math being lacking as I am an accounting professor anything beyond addition, subtraction, multiplication, and division are beyond me. I did have set theory and calculus however. But others have critized that fact also " Where is the Math " Something I obviously need help on. I did ask one member what the formula was for a Venn Diagram, but to date, no answer.
Was that me you asked? If you directly asked me then I'm sure I would've answered, but if not I apologise.
Anyway, there is no specific formula for a Venn Diagram. Such a thing denotes the relationship between two sets. For example, if you imagine a Venn Diagram with two circles denoting two sets A and B, then the bit in the middle that is contained in both is called the set intersection. If we call this R, then we have the equation . I think you probably know this, though. As for a formula describing the whole Venn diagram: one does not exist, since everything contained in the Venn diagram (inculding the outside) is contained in U, the universal set, whatever you define that to be. Everything inside both of the circles is , the set union of the two sets defined as everything contained in A or B or both.
I guess this post isn't very useful, though!
~neutralino
If you haven't found something strange during the day, it hasn't been much of a day - John A. Wheeler.
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. Since proton is (5,1)+(5,1)+(1,3)=(11,5) and (2,
Re: quark soup no gluon -
11-01-2007, 01:36 PM
