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02-05-2008, 03:22 PM
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Originally Posted by mkirkpatrick Ambrosia was the food of the Gods | How do we get some of this? My hunch is that the golden divine ratio of 1.62... and .62... is built into its molecular and atomic or even nuclear or subnuclear structures. Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c² | |
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02-05-2008, 03:32 PM
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Originally Posted by AntonioLao How do we get some of this? My hunch is that the golden divine ratio of 1.62... and .62... is built into its molecular and atomic or even nuclear or subnuclear structures. |
Absolutely Antonio,it is the signature of the IS-ness-less.
I have some ambrosia rice here,comes in a tin,don't think its the "real thing though!
I could try and email you some,(virtual pudding) so to speak!
regards michael. Humilty,coupled with boldness,surprises truth to
reveal herself? | |
| | | | | | Raider of the lost time
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02-05-2008, 03:37 PM
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Originally Posted by mkirkpatrick I could try and email you some | Thanks. All you need to do is email me the chemical formulas then I can reassemble some atoms and molecules with the help of an Alchemist handbook on transmutation of matter and of course some of that hocus pocus stuff. Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c² | |
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02-05-2008, 04:15 PM
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Originally Posted by AntonioLao Thanks. All you need to do is email me the chemical formulas then I can reassemble some atoms and molecules with the help of an Alchemist handbook on transmutation of matter and of course some of that hocus pocus stuff. |
I have some hocus,but am exceedingly short of pocus!If I find the handbook will
send you a copy telepathically?
regards michael. Humilty,coupled with boldness,surprises truth to
reveal herself? | |
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02-06-2008, 11:57 AM
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Originally Posted by mkirkpatrick but am exceedingly short of pocus!If I find the handbook will
send you a copy | I already have the updated handbook by Linus Pauling since He lived near to a hundred and the fact that he got two Nobel Prizes to boot I'll stick with his instructions. By the way, if you replace p with h or h with p then you can have all the pocus hocus you ever need but you still need to stay focus. Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c² | |
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02-06-2008, 12:02 PM
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Originally Posted by AntonioLao I already have the updated handbook by Linus Pauling since He lived near to a hundred and the fact that he got two Nobel Prizes to boot I'll stick with his instructions. By the way, if you replace p with h or h with p then you can have all the pocus hocus you ever need but you still need to stay focus. |
Staying in focus requires being on the ball,as I have vertigo attacks,this is exceedingly
difficult to manage!
regards michael. Humilty,coupled with boldness,surprises truth to
reveal herself? | |
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02-06-2008, 12:23 PM
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Originally Posted by mkirkpatrick Staying in focus requires being on the ball,as I have vertigo attacks,this is exceedingly difficult to manage | I got an idea, you can pass me the ball before the onset of vertigo then as soon as the vertigo calms down then I pass you back the ball, in this way we are acting like two bosons exchanging quantum particle of consciousness. This is universally done by photons, gravitons, Ws, Zs, and gluons. They are all exchange particles of QED, QCD, and QFT. Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c² | |
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02-06-2008, 12:26 PM
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Originally Posted by AntonioLao I got an idea, you can pass me the ball before the onset of vertigo then as soon as the vertigo calms down then I pass you back the ball, in this way we are acting like two bosons exchanging quantum particle of consciousness. This is universally done by photons, gravitons, Ws, Zs, and gluons. They are all exchange particles of QED, QCD, and QFT. |
Ye-Gods Antonio,I think we can crack this nut,we have a dual-hammer!
regards michael. Humilty,coupled with boldness,surprises truth to
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02-25-2008, 07:21 PM
Hello, I was wandering if you are familiar with Ramanujans formulae connecting epsilon, pi, and phi by infinite series.
In particular, the one which connects the e-spiral with an offset of the golden spiral.
Also, I was wandering if you are familiar with the ways in which two circles that overlap continuously outward represent, 'at infinity', the proportions of pi, phi, and the natural logarithm, generally speaking as by a 'whirlpool'-like approach to their respective definitions.
Thanks. | |
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02-25-2008, 07:33 PM
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Originally Posted by perspective exchange Hello, I was wandering if you are familiar with Ramanujans formulae connecting epsilon, pi, and phi by infinite series.
In particular, the one which connects the e-spiral with an offset of the golden spiral.
Also, I was wandering if you are familiar with the ways in which two circles that overlap continuously outward represent, 'at infinity', the proportions of pi, phi, and the natural logarithm, generally speaking as by a 'whirlpool'-like approach to their respective definitions.
Thanks. |
Thanks for your post here PE,welcome to the forum,Antonio is tha main man on this thread,he will get back to you hopefully tomorrow,again welcome and post away.
regards michael. Humilty,coupled with boldness,surprises truth to
reveal herself? | |
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