How many handles would be sufficient to describe the structure of space-time completely? If space-time is a sphere then its number of handle is zero. If space-time is a donut then its handle is unity. Two holes pretzel would be a two handles bundle, 3 holes – 3 handles, 4 holes – 4 handles. The progressive pattern is clearly self-explanatory.
A zero no handle spherical universe would have to be separated into 3 distinctive regions: inner, outer, and the 2D surface of the sphere. Both Einstein’s general relativity of gravity (GR) and quantum mechanics (QM) of elementary particles seem to conform to this genus zero structure of space-time. For QM there are the point-like elementary particles with their inner space-time completely hidden. For the cosmos there is the unreachable boundary of the visible universe. The inner space-time represents time past. The outer space-time represents time future. The now is represented by the edgeless surface where Euclid’s 5th postulate could be replaced by two axioms of non-Euclidean geometries. (1) The no parallel lines axiom and (2) the infinite parallel lines axiom. The 1st is called Riemannian geometry. The 2nd is called hyperbolic geometries invented independently by Gauss, Lobatchevsky, and Bolyai.
The 2nd were discovered first but the first is used for all the mathematical underpinnings of GR and QM. Nevertheless, they are based on a genus zero of a sphere without a hole or a handle to hold on to. Furthermore, not even a single handle space-time structure is sufficient for its description. Therefore, a conjecture can be made such that two holes topology with genus 2 is sufficient for a complete description of microscopic and macroscopic space-time structures. Any physical theory formulated using a double-handle fiber bundle could surpass the hurdle of the space-time riddle.


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