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  1. #1
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    double D algebra

    Differential domain (DD) as a system of Hadamard matrices can be developed into a robust algebra suitable for describing a background-independence theory, even though a background brane matrix that is infinitely extended can still exist, of Quantized Space-Time (QST) or TQS for Theory of Quantized Spacetime. It satisfies the commutative property of multiplication. However, the resulting products can be set equal to the difference of these matrices wherein the subtrahend is always the same matrix while the minuend is the product of an integer eigenvalue and the one other matrix which for power matrices alternate between odd and even.

    Given square symmetric singular Hadamard matrices A and B both of order 2, the matrix multiplication AB=BA. The product is 2B or B-A: AB=BA=2B=B-A. For order 3, AB=3B=2B-A. For order 4, AB=4B=3B-A. For order 5, AB=5B=4B-A. For order 6, AB=6B=5B-A. The general equation for order n is AB=nB=αB-A, where the eigenvalue is α=n-1. The following products and differences give power matrices of A and B. For order 2, A=2A=3A-A, A=4A=5A-A, A=8A=9A-A, A=16A=17A-A. For order 3, A=3A=4A-A, A=9A=10A-A, A=27A=28A-A, A=81A=82A-A. For order 4, A=4A=5A-A, A=16A=17A-A, A=64A=65A-A, A=256A=257A-A. For order 5, A=5A=6A-A, A=25A=26A-A, A=125A=126A-A, A=625A=626A-A. For order 2, B=2A=3A-A, B=4B=5B-A, B=8A=9A-A, B=16B=15B-A. For order 3, B=3A=4A-A, B=9B=8B-A, B=27A=26A-A, B=81B=80B-A. For order 4, B=4A=5A-A, B=16B=15B-A, B=64A=65A-A, B=256B=255B-A. For order 5, B=5A=6A-A, B=25B=24B-A, B=125A=124A-A, B=625B=624B-A.

    An electron is the product of BBBBBBBA=BA. On the other hand, an up quark is the product of AAAAAB=AB and the down quark is the product of ABBB=AB. Therefore, a proton is the product of AAAAAAAAAAABBBBB=AB since it is made up of 2 up-quarks and 1 down-quark. The ratio of AB/ BA=n, where n is the order of the Hadamard matrices. For space charges, there are always 2n representing the 2 squares of spacetime energy whose square root is approximately 1832 for n=6 as the ratio of proton mass to electron mass experimental value is approximately 1836.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  2. #2
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    Smile Re: double D algebra

    Sounds utmostly complex Antonio,lets keep it simple,fusion lies before us,reach out and
    grasp it!



    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

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    Re: double D algebra

    I think I might have asked this before Antonio, but if the proton is ~ 1832 and the electron is 1 why is the neutron ~1836 and not 1833?

    Best,

    Pat

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    Re: double D algebra

    Quote Originally Posted by Profpat View Post
    I think I might have asked this before Antonio, but if the proton is ~ 1832 and the electron is 1 why is the neutron ~1836 and not 1833?

    Best,

    Pat
    I've read something on this I believe it's because the Neutron produces a proton when (one) electron is given off. Some radiation in the form of photons are given off and that is why one electron plus one proton does not equal one neutron.

    A very basic quantum concepts of conversion of mass to energy.

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    Re: double D algebra

    Quote Originally Posted by theunify View Post
    I've read something on this I believe it's because the Neutron produces a proton when (one) electron is given off. Some radiation in the form of photons are given off and that is why one electron plus one proton does not equal one neutron.
    You're along the right lines, but this is not correct. When the neutron decays to the proton a photon is not given off, but an anti-electron-neutrino is. One of the reasons that it is an antineutrino and not a photon is due to something called lepton number conservation. A lepton is assigned a lepton number of +1 and an antilepton a value of -1. A neutron is a baryon, and thus has a lepton number of zero, so the total lepton number after the decay must also be zero. A proton is a baryon (lepton number 0) and a photon is a boson (lepton number 0) so, if the interaction went [imath]n \rightarrow p^+ + e^- + \gamma[/imath], lepton number would not be conserved. The correct decay, [imath]n \rightarrow p^+ + e^- + \nu_e[/imath] does indeed conserve lepton number.

    This still doesn't really answer Pat's question, though, since a neutron is not the same as a proton, electron and an antineutrino. Yes, it can decay to these particles, but that is not the same as saying that it is made up of these particles. The real "reason" is that the proton and neutron are made up of different multiples of different quarks, which have different masses. They are both made up of multiples of the "up" and "down" quark, but the proton is "uud" and the neutron is "udd." The slightly different mass of the quarks causes a difference in mass between the proton and the neutron.
    ~neutralino

    If you haven't found something strange during the day, it hasn't been much of a day - John A. Wheeler.

  6. #6
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    Re: double D algebra

    Quote Originally Posted by mkirkpatrick
    lets keep it simple
    Any simpler I have to throw away every order of Hadamard matrices and end up empty handed. The distinction between quantum mechanics and general relativity is that the former is background-dependence while the latter is background-independence. Matrix multiplication can be used to describe background-independence and matrix subtraction can be used to describe background-dependence. But as I briefly indicated they are equivalent only different in their respective eigenvalues.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Smile Re: double D algebra

    Quote Originally Posted by AntonioLao View Post
    Any simpler I have to throw away every order of Hadamard matrices and end up empty handed. The distinction between quantum mechanics and general relativity is that the former is background-dependence while the latter is background-independence. Matrix multiplication can be used to describe background-independence and matrix subtraction can be used to describe background-dependence. But as I briefly indicated they are equivalent only different in their respective eigenvalues.
    You need to be full handed of course,however simplicity is the signature of reality.



    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  8. #8
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    Re: double D algebra

    Actually empty handed is very simple.

  9. #9
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    Re: double D algebra

    Quote Originally Posted by Profpat
    Actually empty handed is very simple.
    Could this be the reason why honest simple-minded people are poor?
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  10. #10
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    Re: double D algebra

    Yes, poor but honest. No gun in their hand, nothing in their hand behind their back.

 

 
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