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  1. #1
    Raider of the lost time
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    linear operators

    Ordinary operators of arithmetic like +, -. X, and ÷ are known as binary operators that needed two objects (before and after or left and right), for example B+A or BxA. Note that + and x are commutative that is to say B+A=A+B or BxA=AxB. On the other hand, - and ÷ are not since B-AA-B nor B÷AA÷B. If commutativity is applied to the time parameter the result is known as time inversion symmetry and led to a conservation law for mass and energy in an isolated system. If it is applied to spatial orientation or direction of left and right, top and bottom, or front and back then the result is known as parity symmetry and led to a conservation law of linear momentum. A more subtle symmetry can be applied to spatial rotation and reflection which must led to a conservation law for angular momentum.

    On the other hand, there are unary operators that can be applied only to single objects, for example, taking the n-root or n-power. However, if a unary operator wherever and whenever applied gives scalar multiples the same object or multiple combinations of different objects then is called a linear operator. Almost if not all physical operators of quantum mechanics are linear operators.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  2. #2
    8th degree Black Belt
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    Re: linear operators

    I just like to read your posts. I try to relate and I think I am a linear operator without knowing what you are really on about. Do you still post from the library? I still jack the neighbors internet.


    sally.

  3. #3
    Raider of the lost time
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    Re: linear operators

    Quote Originally Posted by sillysally
    I think I am a linear operator
    My idea of a linear operator is someone with a set goal or purpose in life and usually get what they want. Some are unidirectional, 1 goal or 1 purpose. Some are multidirectional, many goals and many purpose. Typing from the public library of Plano that's my goal for today.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  4. #4
    Grandmaster
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    Re: linear operators

    Quote Originally Posted by sillysally View Post
    I just like to read your posts. I try to relate and I think I am a linear operator without knowing what you are really on about. Do you still post from the library? I still jack the neighbors internet.
    My guess is that you are a very curvaceous operator Sally.

 

 

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