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  1. #1
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    Group number vs. sieve index

    Within a Diophantine sieve the maximum sieve index is equal to 3G-1 where G is the group number. Then the 6 numbers of each group would have indices: (3G-1,0), (3G-1,1), (3G-2,0), (3G-2,1), (3G-3,0), (3G-3,1). For G=1 they are (2,0), (2,1), (1,1), (1,0), (0,0), (0,1). The sieve index of 0 is (0,0), 2 is (1,0), 3 is (0,1), 4 is (2,0), 5 is (1,1), 7 is (2,1) and the 6 numbers are: 0, 2, 3, 4, 5, 7. For G=20, the sieve indices are (59,0), (59,1), (58,0), (58,1), (57,0), (57,1). These respectively are represented by the 6 numbers: 118, 121, 116, 119, 114, 177, none are known primes. For any given group number G, the two numbers at sieve indices: (3G-3,0) and (3G-3,1), are always divisible by 3. The two at (3G-1,0) and (3G-2,0) are always divisible by 2. Leaving only two prime candidates at sieve indices: (3G-2,1) and (3G-1,1). If both are primes then they are twin primes.

    Given a number 12193, its primary sieve index is given by (m, n). For odd numbers, n is always unity, n=1. For even numbers, n is always zero, n=0 while m is any number between 0 and infinity. So, the primary index of 12193 is found by subtracting 3 then dividing by 2 giving 6095 and its primary index is (6095, 1). Next, is to find its group number by assuming that m=6095 is its maximum index value: 3G-1=max(m) then solve for G. The solution gives 2032 and the 6 numbers of this group are: 12186, 12189, 12188, 12191, 12190, and 12193. These are repeated diagonally 2032 times in the Diophantine sieve.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  2. #2
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    Smile Re: Group number vs. sieve index

    So when you sieve out all the numbers,whats left?Is it a symbol of reality as it is?




    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  3. #3
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    Re: Group number vs. sieve index

    Only the number 1 is sieved out so a Diophantine sieve is the union of two disjointed set [0, 1) and (1, infinity).
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Smile Re: Group number vs. sieve index

    Quote Originally Posted by AntonioLao View Post
    Only the number 1 is sieved out so a Diophantine sieve is the union of two disjointed set [0, 1) and (1, infinity).
    So then 1=on and 0=off then?




    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  5. #5
    Raider of the lost time
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    Re: Group number vs. sieve index

    That's true only in computer science and the binary system of numbers.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  6. #6
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    Smile Re: Group number vs. sieve index

    Quote Originally Posted by AntonioLao View Post
    That's true only in computer science and the binary system of numbers.
    What about a universe manifested,then unmanifested?




    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  7. #7
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    Re: Group number vs. sieve index

    For that requires squaring of negative energy into positive square of energy. Incidentally, Dirac went the other way he took the square root of energy squared and came up with matter and antimatter.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  8. #8
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    Smile Re: Group number vs. sieve index

    Quote Originally Posted by AntonioLao View Post
    For that requires squaring of negative energy into positive square of energy. Incidentally, Dirac went the other way he took the square root of energy squared and came up with matter and antimatter.

    So it could be done that way then?




    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  9. #9
    Raider of the lost time
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    Re: Group number vs. sieve index

    But how can we extract 1st power energy from square of energy as in a process for cold fusion?
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  10. #10
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    Smile Re: Group number vs. sieve index

    Quote Originally Posted by AntonioLao View Post
    But how can we extract 1st power energy from square of energy as in a process for cold fusion?

    That is a most interesting question,1st power energy resides within us,guess we need
    to meditate on how to harness it,then focus on the fusion factor.




    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

 

 
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