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  1. #1
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    Yin-yang double-Hopf

    Quantum field theory (QFT) uses Lie algebras of quantum generators that satisfy the non-Abelian commutation relation derived from the unitary groups: U(1), SU(2), and SU(3). However, these are defined if and only if their representations are determined on the complex plane as gauge invariance of the phase factors of the real rotation groups using Euler’s formula: exp(±iq)=cosq±isinq for the unit circle centered at the origin (0,0).

    Since the complex plane is 2D, any extension to 3D rotation groups centered at the origin (0,0,0) necessitated one more real, in fact imaginary orthogonal axis. Besides, 1 imaginary 2 real axis is not real 3D. Consequently, quantum mechanics (QM) 1 imaginary 1 real axis is not real 2D either. Therefore, QM is really a 1D and QFT is really a 2D formalism.

    A true 3D motionless (absolute rest) formulation would then demand the square of the complex modulus normalized in units of Planck length on the symmetric gauge between the centers of two orthogonal unit circles thus removed the need of a coordinate origin at (0,0,0) conforming to the requirement of the principle of general covariance. This can be use to represent a single Hopf loop. Moreover, the principle of directional invariance requires at least two Hopf loops for a complete real 3D description of quantum space-time: a yin loop and a yang loop. Either of these 2 topologically distinct loops can represent a magnetic monopole or a graviton. However, together a yin-yang loop represents a neutrino. 7-yin 1-yang is an electron. 1-yin 5-yang is an up quark. 3-yin 1-yang is a down quark. 4-yin 4-yang is a photon. 2-yin 8-yang is a W+, 8-yin 2-yang is a W-, and 8-yin 8-yang is a Zº boson. The absolute value of the space-time charges of each loop is 1/6. Adding space-time charges give fractal or integral electric charge while color charges are replaced by the directional invariance properties based on the visibility of the 4-fold symmetry of yin-yang double-Hopf.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  2. #2
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    Smile Re: Yin-yang double-Hopf

    What a magnificent discription Antonio,you seem to have SUMMED it up!Great post.




    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  3. #3
    Raider of the lost time
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    Re: Yin-yang double-Hopf

    That would be the next in line for publishing unless considered as published here in TOEquest?
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  4. #4
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    Smile Re: Yin-yang double-Hopf

    Quote Originally Posted by AntonioLao View Post
    That would be the next in line for publishing unless considered as published here in TOEquest?
    Can that be done?Ask Robert!




    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  5. #5
    Raider of the lost time
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    Re: Yin-yang double-Hopf

    I'm afraid to ask. But if it is a banter then he will automatically removed it in 3 days.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  6. #6
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    Smile Re: Yin-yang double-Hopf

    Quote Originally Posted by AntonioLao View Post
    I'm afraid to ask. But if it is a banter then he will automatically removed it in 3 days.
    Banter!This could be the very crust from whence all future bread be baked from!
    Shall we both ask him!




    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  7. #7
    Raider of the lost time
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    Re: Yin-yang double-Hopf

    You go first. Aged wisdom before shy ugliness.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  8. #8
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    Smile Re: Yin-yang double-Hopf

    Quote Originally Posted by AntonioLao View Post
    You go first. Aged wisdom before shy ugliness.

    You sure know how to butter up a chap!I will send him a pm.



    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

 

 

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