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    Biortho test


    The derivatives as defined in the infinitesimal calculi of integration and differentiation allow the test for perpendicularity or orthogonality of two functions intersecting at a particular point in space and time. This particular test can be called the biortho test, the binary multiplication of a pair of derivatives at a particular instant. If these derivatives have values of either zero or infinity then the tests fail. But any value between negative infinity and positive infinity excluding the middle value of zero will always work if and only if the product is negative unity.

    As an example: two linear functions are given as y=x/3+4 and y=-3x-3 whose respective derivatives are: dy/dx=1/3 and dy/dx=-3 and their product is (1/3)(-3) = -1, the negative unity. Therefore, these two linear functions are said to be orthogonal on the x-y plane. Similarly, the linear functions z=-x/3+1 and z=3x+2 are said to be orthogonal in the x-z plane and y=-5z-4 and y=z/5-4 are said to be orthogonal in the y-z plane. Nonetheless, three planes: x-y,x-z, and y-z are sufficient and necessary for spanning or describing a point in three dimensions. For describing a point in four dimensions then there are 3 more planes needed namely: x-t,z-t, and y-t, where t signifies the time axis. A total of six planes are needed for spanning the orthogonality of space and time. However, if time is in the infinitesimal neighborhood of zero then 3 infinitesimal space planes: x-y,x-z, and y-z are all but sufficient to completely span the infinitesimal local motion of space-time.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Smile Re: Biortho test

    Space and time seem to exist,the operative word here is "seem" it is in fact an illusion,as we exist in the "outer sphere" the relative universe,these measurements "seem" true and valid,however we also exist within an inner absolute reality,it is here that all measurements pale into
    absurdity.



    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

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    Re: Biortho test

    mike,

    The first round of ortho tests are called vectors or rank 1 tensors. Successive ot's give tensors of higher and higher ranks. There is also a distinction between covariant and contravariant tensors of any rank.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Smile Re: Biortho test

    Quote Originally Posted by AntonioLao View Post
    mike,

    The first round of ortho tests are called vectors or rank 1 tensors. Successive ot's give tensors of higher and higher ranks. There is also a distinction between covariant and contravariant tensors of any rank.

    Cheers my friend,I feel less tense now?



    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

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    Re: Biortho test

    That might be because consciousness resides in a spacetime domain of zero rank tensor, traditionally called a scalar or simply a dimensionless number.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Smile Re: Biortho test

    Quote Originally Posted by AntonioLao View Post
    That might be because consciousness resides in a spacetime domain of zero rank tensor, traditionally called a scalar or simply a dimensionless number.

    That was a most excellent answer,am grateful sir.



    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

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    Re: Biortho test

    It must be kept in mind that without partial differentiation, a biortho test can only be effectively applied to one directional attribute out of possible eight attributes.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Smile Re: Biortho test

    Quote Originally Posted by AntonioLao View Post
    It must be kept in mind that without partial differentiation, a biortho test can only be effectively applied to one directional attribute out of possible eight attributes.
    this again implies unbalance.



    regards michael.
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    reveal herself?

  9. #9
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    Re: Biortho test

    That could be due to the incompleteness of the language of mathematics. Godel had only proved it to be logically not numerically so.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  10. #10
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    Smile Re: Biortho test

    Quote Originally Posted by AntonioLao View Post
    That could be due to the incompleteness of the language of mathematics. Godel had only proved it to be logically not numerically so.
    That seems a logical conclusion,I tend to agree with that.



    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

 

 
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