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Thread: point vs vector

  1. #1
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    point vs vector


    In two dimensions, math definitions give no considerable differences for a point and a vector. Both can be defined as an ordered pair of real numbers mandn. The pointPis given by (m, n) while the vectorVis given by <m, n>. The former implies the existence of a 2D coordinate system as a frame of reference. The latter is independent of such a system althoughmandnrepresent the two components of a unique vector. The pointPalso implies the existence of an origin given by (0, 0).Vis always free of such origin although <0, 0> represents a unique vector of zero length with infinitely possible directions to choose from.

    In a Cartesian coordinate system,mrepresents the abscissa whilenrepresents the ordinate. In a polar coordinate system,mrepresentsRcosqandnrepresentsRsinqwhereRis known as the radius vector and qis the angular distance of Rmeasured counterclockwise from the abscissa of zero ordinate usually called the x-axis. Ifq=90° orp/4 thenRcoincides with the vertical y-axis of zero abscissa. By these definitions, Ris a bound vector with one end fixed at the origin (0, 0). On the other hand, <m, n> remains a free vector with its transformed direction given as the ratio ofn/mor tanqwhich is also known as the slope of any line parallel toR.

    In one dimension,Pis simply represented by (m) whileVis represented by <m>. Both could imply directional invariance. However, (-m) and <-m> could be used to represent respectively linear reflection or 180° rotation ofPand V. Moreover, <-m> can be used to represent the reverse direction of time. In three dimensions,Pis (m, n, w) andVis <m, n, w>. In four dimensions,Pis (m, n, w, u) andVis <m, n, w, u>. These higher dimensional representations give complicated directional orientations, making the use of a well defined coordinate system absolutely necessary as required by a principle of covariance.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Smile Re: point vs vector

    Is this leading to a cold fusional conclusion?



    regards michael.
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  3. #3
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    Re: point vs vector

    The immediate step is a time reversed resolution.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Smile Re: point vs vector

    Quote Originally Posted by AntonioLao View Post
    The immediate step is a time reversed resolution.
    Thats what you are working on here?



    regards michael.
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  5. #5
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    Re: point vs vector

    Looking back the 3 neutrinos were at the same space-time location. Creating the same space-time location is the same as bringing them back to the same location.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Smile Re: point vs vector

    Quote Originally Posted by AntonioLao View Post
    Looking back the 3 neutrinos were at the same space-time location. Creating the same space-time location is the same as bringing them back to the same location.

    Not easily done!


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  7. #7
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    Re: point vs vector

    But the key concept is to accept the topological connectivity of all space-time points.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Smile Re: point vs vector

    Quote Originally Posted by AntonioLao View Post
    But the key concept is to accept the topological connectivity of all space-time points.

    Acceptence is the key then?



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  9. #9
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    Re: point vs vector

    That all space-time points are connected although each point is quantized.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  10. #10
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    Smile Re: point vs vector

    Quote Originally Posted by AntonioLao View Post
    That all space-time points are connected although each point is quantized.
    Yes,that's about the size of it.




    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

 

 
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