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The 1D quantum vacuum can be partitioned into infinitely many subintervals. The norm of this partition is equal to the length of the largest subinterval and is denoted by ||P||. However, if these subintervals are of equal length then ||P|| represents the irreducible unit of the quantum vacuum. For all practical purposes, the norm is equivalent to the Planck length.
The 2D quantum vacuum is then the development of unit squares with sides as given by the norm vacuum. The 3D quantum vacuum is then the development of cubic norm vacuum extending infinitely in every possible directions of space-time. Moreover, with every 3D tessellation of unit cubic norm vacuum can be found a volume minimizing compactification of a tetrahedral tessellation of side √2 of the unit norm vacuum. The cubic norm vacuum can represent the quantum vacuum space-time structure of some leptons while the tetrahedral norm vacuum can represent space-time structure of some quark’s flavors. The three others non-tessellatable Platonic solids would be the octahedron, icosahedron, and the dodecahedron.
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Thread: norm vacuum
- 12-17-2008, 11:52 AM #1Raider of the lost time
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norm vacuum
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
- 12-17-2008, 12:04 PM #2Moderator
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Re: norm vacuum Well then,what vacuum do we need for cold fusion to work?
regards michael.Humilty,coupled with boldness,surprises truth to
reveal herself?
- 12-17-2008, 12:09 PM #3Raider of the lost time
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Re: norm vacuum
For cold fusion, the answer is artificial tessellations beside the natural ones of cubic and tetrahedral norm vacua.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
- 12-17-2008, 12:15 PM #4Moderator
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Re: norm vacuum 
Originally Posted by AntonioLao 
Thats cleared up,thanks.
regards michael.Humilty,coupled with boldness,surprises truth to
reveal herself?
- 12-18-2008, 02:00 PM #5Raider of the lost time
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Re: norm vacuum
But the tetrahedral tessellation can make sense if applied to the down quark and the cubic tessellation to photon and electron and their antiparticles.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
- 12-18-2008, 04:33 PM #6Moderator
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Re: norm vacuum It has to make sense or we are sunk. Originally Posted by AntonioLao
regards michael.Humilty,coupled with boldness,surprises truth to
reveal herself?
- 01-03-2009, 12:04 PM #7Raider of the lost time
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Re: norm vacuum
It is not possible to sink deeper than the Planck domain of spacetime structures.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
- 01-03-2009, 03:29 PM #8Moderator
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Re: norm vacuum What about beneath spacetime? Originally Posted by AntonioLao
regards michael.Humilty,coupled with boldness,surprises truth to
reveal herself?
- 01-03-2009, 03:44 PM #9Raider of the lost time
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Re: norm vacuum
Not possible if spacetime is the finality of reality's background.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
- 01-03-2009, 03:48 PM #10Moderator
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Re: norm vacuum Surely consciousness exists within and without spacetime. Originally Posted by AntonioLao
Absoluteness too exists without spacetime.
regards michael.Humilty,coupled with boldness,surprises truth to
reveal herself?
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