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Thread: d-H-v-A

  1. #1
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    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Smile Re: d-H-v-A

    Could not open the link given my friend,have you copied
    it correctly?



    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  3. #3
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    Re: d-H-v-A

    Sorry. I can't open it either. Will try another link. It has to do with the mysterious magnetic vector potential.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    Smile Re: d-H-v-A

    Quote Originally Posted by AntonioLao View Post
    Sorry. I can't open it either. Will try another link. It has to do with the mysterious magnetic vector potential.
    Ok will check it out when you suceed.




    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  5. #5
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    Re: d-H-v-A

    Thanks. I almost forgotten. Will do it rigthaway. I hope this link will work http://en.wikipedia.org/wiki/De_Haas-van_Alphen_effect
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  6. #6
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    Smile Re: d-H-v-A

    Quote Originally Posted by AntonioLao View Post
    Thanks. I almost forgotten. Will do it rigthaway. I hope this link will work http://en.wikipedia.org/wiki/De_Haas-van_Alphen_effect

    Yes this link is fine,thanks.




    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  7. #7
    Raider of the lost time
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    Re: d-H-v-A

    lately, I notice from my searches that relevant discoveries seem to have more than one discover. The same is true for receipients of Nobel Prizes.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

 

 

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